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kiruha [24]
4 years ago
15

How many four-letter codes can be made if no letter can be used twice?

Mathematics
1 answer:
Y_Kistochka [10]4 years ago
8 0

Answer:4 ways to make a code of 4 letters. 6C4=15, 4!=24, and 15×24=360

hope i helped

Step-by-step explanation:

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Given: m∠V=103°, m∠VRT=71°, RS ∥ VU Find: m∠TRS, m∠U
IrinaVladis [17]

Answer:

m∠TRS = 6°

m∠U = 103°

Step-by-step explanation:

In the given figure,

O is the center

RS ∥ VU

m∠V = 103° &

m∠VRT = 71°

So,

m∠V +  m∠R = 180°                (∵ sum of co-interior angles)

⇒  m∠R = 180° - 103°              (m∠V = 103° is given)

∵ m∠R = 77°    ...(i)

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