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4 years ago

I need help on number 2. A

Mathematics

1 answer:

Drupady [299]4 years ago

5 0

You should use a protractor to help you with this answer; without one it's really hard to draw a 62 degree angle on your own. Sorry!!!

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The perimeter of a rectangle a picture frame is 66 inches. the length is 3 inches greater than the width the system of linear eq

m_a_m_a [10]

Given:

The perimeter of a rectangular picture frame is 66 inches [2X + 2Y = 66.]
The length of the frame is 3 inches greater than the width [X + 3 = Y.]

To find: The dimensions.

Answer:

Formula to find the perimeter of a rectangle = 2 × (Length + Width)

We know that 2X + 2Y = 66. Simplifying it, we get:

2(X + Y) = 66

X + Y = 66/2

X + Y = 33

Now that we know the value of X + Y, and assuming X and Y to be the dimensions, let's substitute it into the formula to find the perimeter and verify it.

Perimeter = 2 × (X + Y)

66 = 2 × 33

It's verified.

Now, we also have the expression representing the length, which is X + 3 = Y.

X + Y = 33

X + 3 = Y

Let's add both expressions.

X + Y + X + 3 = 33 + Y

2X + Y + 3 = 33 + Y

2X = 33 - 3 + Y - Y

2X = 30

X = 30/2

X = 15

Hence, the width [X] is 15.

Substituting this value into the expression representing the length,

15 + 3 = Y

18 = Y

Hence, the length and breadth of the rectangular picture frame is 18 and 15 units respectively.

Hope it helps. :)

6 0

3 years ago

WILL MARK BRAINLIEST

Kay [80]

Answer:

1 If the equations do not involve fractions or decimals, and you have a good visual understanding of linear equations, graphing on the coordinate plane is a good option.

2 Whenever one equation is already solved for a variable, substitution will be the quickest and easiest method.

3 Elimination is best used when both equations are in standard form (Ax + By = C). Elimination is also the best method to use if all of the variables have a coefficient other than 1.

8 0

2 years ago

Which one is > greater or < less than or = equal to?? 6+√8____√6+8

brilliants [131]

$\huge\boxed{\sqrt{6}+8\;is\;greater\;than \;6+\sqrt{8} }$

$6+\sqrt[]{8} =8.82\\\sqrt{6}+8=10.44\\\\\boxed{Therefore, \sqrt{6}+8\;is\;greater\;than\;6+\sqrt{8}. }$

4 0

3 years ago

Find f'(x) and simplify!

Ede4ka [16]

$\bf f(x)=\cfrac{sin(x)}{x^2}\implies \cfrac{dy}{dx}=\cfrac{x^2cos(x)-2xsin(x)}{(x^2)^2}
\\\\\\
\cfrac{dy}{dx}=\cfrac{x[xcos(x)-2sin(x)]}{x^4}\implies \cfrac{dy}{dx}=\cfrac{xcos(x)-2sin(x)}{x^3}
\\\\
-----------------------------\\\\$

$\bf f(x)=(3x^2+2x-1)^4\implies \cfrac{dy}{dx}=4(3x^2+2x-1)^3(6x+2)
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-----------------------------\\\\
f(x)=\left( \cfrac{x-5}{2x+1} \right)^2\implies \cfrac{dy}{dx}=2\left( \cfrac{x-5}{2x+1} \right)\left[ \cfrac{2x+1-2(x-5)}{(2x-1)^2} \right]
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\cfrac{dy}{dx}=2\left( \cfrac{x-5}{2x+1} \right)\left[ \cfrac{11}{(2x-1)^2} \right]$

4 0

3 years ago

Two planes, A and B, start from the same place and move in different directions, making an angle of 50º between them. The speed

cluponka [151]

Answer: The distance between them is 230.65 miles.

Step-by-step explanation:

Since we have given that

Speed of plane A (b) = 200 miles per hour

Speed of plane B (c) = 300 miles per hour

Angle between them = 50°

So,

We will use the "Cosine formula", we get

$a^2=b^2+c^2-2bc\cos A\\\\a^2=200^2+300^2-2\times 200\times 300\cos 50\textdegree\\\\a^2=40000+90000-120000\cos 50\textdegree\\\\a^2=130000-120000\times 0.64\\\\a^2=130000-76800\\\\a^2=53200\\\\a=\sqrt{53200}\\\\a=230.65\ miles\ per\ hour$

So, distance between the two planes after one hour will be

$Distance=\frac{Speed}{time}=\frac{230.65}{1}=230.65\ miles$

So, the distance between them is 230.65 miles.

6 0

4 years ago

Read 2 more answers