The roots of an equation are simply the x-intercepts of the equation.
See below for the proof that
has at least two real roots
The equation is given as: 
There are several ways to show that an equation has real roots, one of these ways is by using graphs.
See attachment for the graph of 
Next, we count the x-intercepts of the graph (i.e. the points where the equation crosses the x-axis)
From the attached graph, we can see that
crosses the x-axis at approximately <em>-2000 and 2000 </em>between the domain -2500 and 2500
This means that
has at least two real roots
Read more about roots of an equation at:
brainly.com/question/12912962
Do elimination
2x + y = 3
x - y = 3
Add these
3x = 6
X = 2
Plug in 2 for x
4(2) + 2y = 6
8 + 2y = 6
2y = -2
X = 2, y = -1
Curve it to get the answe than radical it to get the second number