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yawa3891 [41]
3 years ago
12

Which of the following polynomials has a remainder of -11 when divided by x+1? A. −2x3+4x2+3x−2 B. 3x3+6x−2 C. x3−2x2−4x+1 D. 4x

3+2x2+5

Mathematics
1 answer:
lana66690 [7]3 years ago
8 0

Answer:

B. 3x3+6x−2

Step-by-step explanation:

When you divide 3x3+6x−2 by x+1 we get a remainder of -11.

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16x 2 + 8x - 15 Mathematics?
Gala2k [10]
If you're factoring, your answer is

(4x - 3)(4x + 5)

You'll work it out this way:

16x^2 + 8x - 15

Since there's no GCF here, you multiply the first and third terms, giving you -240. Your next step is to find two numbers that have a sum of 8 and a product of -240. These numbers are 20 and -12. Plug those in and you've got:

16x^2 + 20x - 12x - 15

From here you divide it into two binomials. These are (16x^2 + 20x) and (-12x - 15).
When you take out the greatest common factors (4x and -3), they become:

4x(4x + 5) - 3(4x + 5)

Then you group what's outside of the parentheses together (4x - 3)
And bring what's inside of the parentheses down (4x + 5).
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(4x - 3)(4x + 5)
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vodomira [7]
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navik [9.2K]

Answer:

a) Sample mean: 48.71

Sample median: 48.3

Sample variance: 5.41

Sample standard deviation: 2.37

Step-by-step explanation:

a) Sample mean:

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Sample standard deviation

s=\sqrt{s^2}=\sqrt{5.41}=2.37

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