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s344n2d4d5 [400]
3 years ago
15

What is the perimeter of this hexagon?

Mathematics
2 answers:
Nikolay [14]3 years ago
5 0
8.6+7.2+6.3+10.5+6.3+7.4= A) 46.3 cm 
Akimi4 [234]3 years ago
4 0
The answer is A. 46.3 cm
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P and q are points on the line y=2-4X <br><br>Draw the line y= 2-4X for vales of x from -2 to 2
pishuonlain [190]

Answer:

`The answer is below

Step-by-step explanation:

P and q are points on the line y=2-4X. complete the coordinates of P and Q, P(0, ) Q( ,0)

Draw the line y= 2-4X for vales of x from -2 to 2

Solution:

The equation of a line is given by:

y = mx + b

Where y and x are variables, m is the slope of the line and b is the y intercept (that is value of y when x = 0).

The line of y = 2 - 4x is drawn by finding the corresponding values of y for x from -2 to 2 and plotting on a graph.

x:   -2      -1       0        1        2

y:   10      6       2       -2       -6

The value P(0, ) Q( ,0)

The y coordinate of point P is gotten by substituting x = 0:

y = 2 - 4(0) = 2

P = (0, 2)

The x coordinate of point Q is gotten by substituting y = 0:

0 = 2 - 4x

4x = 2

x = 0.5

Q = (0.5, 0)

8 0
3 years ago
The scale of a map is 1 in. = mi. Find each length on the map
WITCHER [35]

The question gives the relationship to be

1in=21mi

We will interpolate to solve the question.

First Question: 147 mi

\begin{gathered} \text{If 1 in = 21 mi} \\ x\text{ in = 147 mi} \end{gathered}

Cross multiplying,

undefined

7 0
1 year ago
What is the minimum value for the function shown in the graph?<br><br> Enter your answer in the box.
Fudgin [204]

The minimum value is the lowest point of a graphed line. The would be the bottom of the "U" shape.

Looking at the graph you can see that the bottom of the U is touching the horizontal line at x = -5.5, so this would be the minimum value.

The lowest part of the line is at -5.5

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3 years ago
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pentagon [3]
Carla still has $100 because she didn't get any more money in the other months
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3 years ago
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IgorC [24]
750*7.9%*8=474 is the account at the end of 8 years. Good luck
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4 years ago
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