What is the square root of m^6

Mathematics

2 answers:

Anarel [89]3 years ago

8 0

Answer:m^3

Step-by-step explanation:

Square root of m^6=√(m^6)

(m^6)^(1/2)

m^(6 x 1/2)

m^(6/2)

m^3

Kazeer [188]3 years ago

6 0

Answer:

m^3

Step-by-step explanation:

When taking the square root of m^6, you can make 3 pairs.

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Solve for x <br> This is also an octagon if it helps!

Karo-lina-s [1.5K]

Answer:

x = 10

Step-by-step explanation:

it has 8 sides so:

total interior angle degrees = (180° x 8 sides) - 360° = 1080°

11x + 14 + 4x + 87 +2x + 70 + 4x + 31 + x + 92 + 3x + 167 + 5x + 48 + 2x + 251 = 1080°

combine like terms:

32x + 760° = 1080°

subtract 760° from both sides of the equation:

32x = 320°

divide both sides by 32:

x = 10

8 0

2 years ago

Weights of the vegetables in a field are normally distributed. From a sample Carl Cornfield determines the mean weight of a box

pantera1 [17]

To find the z-score for a weight of 196 oz., use

$z=\frac{x-\mu}{\sigma}=\frac{196-180}{8}=\frac{16}{8}=2$

A table for the cumulative distribution function for the normal distribution (see picture) gives the area 0.9772 BELOW the z-score z = 2. Carl is wondering about the percentage of boxes with weights ABOVE z = 2. The total area under the normal curve is 1, so subtract .9772 from 1.0000.

1.0000 - .9772 = 0.0228, so about 2.3% of the boxes will weigh more than 196 oz.