Answer:
The proof is below.
Step-by-step explanation:
Given two triangles similar.
we have to prove that ratio 
As, △OKE∼△VDE
∴ their corresponding sides are in same proportion.
⇒ 
⇒ [tex}\frac{EK}{EO}=\frac{VE}{ED}[/tex]
Hence Proved.
Answer:
B. 3
Explanation:
2 + 3 = 5
5 + 3 = 8
8 + 3 = 11
This is how you find the common rate between a sequence of numbers. If you find how to get to on number, you see if it works on another, and so on. If it does, that is the rate.
Answer:3aC +bC
Step-by-step explanation:
47 - 5*3 - 2*1 = 30. 30/3 = 3, so add three plus five plus two = 10 kids
Compute the derivative dy/dx using the power, product, and chain rules. Given
x³ + y³ = 11xy
differentiate both sides with respect to x to get
3x² + 3y² dy/dx = 11y + 11x dy/dx
Solve for dy/dx :
(3y² - 11x) dy/dx = 11y - 3x²
dy/dx = (11y - 3x²)/(3y² - 11x)
The tangent line to the curve is horizontal when the slope dy/dx = 0; this happens when
11y - 3x² = 0
or
y = 3/11 x²
(provided that 3y² - 11x ≠ 0)
Substitute y into into the original equation:
x³ + (3/11 x²)³ = 11x (3/11 x²)
x³ + (3/11)³ x⁶ = 3x³
(3/11)³ x⁶ - 2x³ = 0
x³ ((3/11)³ x³ - 2) = 0
One (actually three) of the solutions is x = 0, which corresponds to the origin (0,0). This leaves us with
(3/11)³ x³ - 2 = 0
(3/11 x)³ - 2 = 0
(3/11 x)³ = 2
3/11 x = ³√2
x = (11•³√2)/3
Solving for y gives
y = 3/11 x²
y = 3/11 ((11•³√2)/3)²
y = (11•³√4)/3
So the only other point where the tangent line is horizontal is ((11•³√2)/3, (11•³√4)/3).
