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Stels [109]
3 years ago
10

Solve x^2 - (7 -1)x + (18 - i) =0

Mathematics
1 answer:
Mazyrski [523]3 years ago
6 0

Step-by-step explanation:

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Given: △OKE∼△VDE<br> Prove: EK/EO = ED/EV
harkovskaia [24]

Answer:

The proof is below.

Step-by-step explanation:

Given two triangles similar.

we have to prove that ratio \frac{EK}{EO}=\frac{VE}{ED}

As, △OKE∼△VDE

∴ their corresponding sides are in same proportion.

\frac{OK}{VD}=\frac{EK}{ED}=\frac{OE}{VE}

⇒ \frac{EK}{ED}=\frac{EO}{VE}

⇒ [tex}\frac{EK}{EO}=\frac{VE}{ED}[/tex]

Hence Proved.

6 0
3 years ago
What is the common difference or common ratio of the sequence 2, 5, 8, 11, ...?
dem82 [27]
Answer: 
B. 3

Explanation: 
2 + 3 = 5 
5 + 3 = 8 
8 + 3 = 11 

This is how you find the common rate between a sequence of numbers. If you find how to get to on number, you see if it works on another, and so on. If it does, that is the rate.
7 0
3 years ago
Read 2 more answers
Use the distributive property to write the following expression in expanded form. C(3a+b)
Eduardwww [97]

Answer:3aC +bC

Step-by-step explanation:

5 0
3 years ago
its was taylor's 8th birthday and there were 47 presents. Each kid brought 10 presents, except for three kids who brought five p
goblinko [34]
47 - 5*3 - 2*1 = 30. 30/3 = 3, so add three plus five plus two = 10 kids
4 0
2 years ago
Find a point on the curve x^3+y^3=11xy other than the origin at which the tangent line is horizontal.
attashe74 [19]

Compute the derivative dy/dx using the power, product, and chain rules. Given

x³ + y³ = 11xy

differentiate both sides with respect to x to get

3x² + 3y² dy/dx = 11y + 11x dy/dx

Solve for dy/dx :

(3y² - 11x) dy/dx = 11y - 3x²

dy/dx = (11y - 3x²)/(3y² - 11x)

The tangent line to the curve is horizontal when the slope dy/dx = 0; this happens when

11y - 3x² = 0

or

y = 3/11 x²

(provided that 3y² - 11x ≠ 0)

Substitute y into into the original equation:

x³ + (3/11 x²)³ = 11x (3/11 x²)

x³ + (3/11)³ x⁶ = 3x³

(3/11)³ x⁶ - 2x³ = 0

x³ ((3/11)³ x³ - 2) = 0

One (actually three) of the solutions is x = 0, which corresponds to the origin (0,0). This leaves us with

(3/11)³ x³ - 2 = 0

(3/11 x)³ - 2 = 0

(3/11 x)³ = 2

3/11 x = ³√2

x = (11•³√2)/3

Solving for y gives

y = 3/11 x²

y = 3/11 ((11•³√2)/3)²

y = (11•³√4)/3

So the only other point where the tangent line is horizontal is ((11•³√2)/3, (11•³√4)/3).

3 0
2 years ago
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