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balandron [24]
3 years ago
7

Anybody help me please!!!!!!!!!!!!!!!

Mathematics
1 answer:
Elodia [21]3 years ago
8 0

Answer:

Reflection over the X axis.

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NEED HELP ASAP Find the value of x. Round to the nearest tenths place. ​
Oliga [24]

Answer:

x = 77.8 ft

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Order of Operations: BPEMDAS

<u>Trigonometry</u>

  • sin∅ = opposite over hypotenuse

Step-by-step explanation:

<u>Step 1: Define</u>

∅ = 40°

opposite leg of angle = 50 ft

hypotenuse = x ft

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Substitute:                                        sin40° = 50/x
  2. Multiply <em>x </em>on both sides:                 xsin40° = 50
  3. Divide sin40° on both sides:           x = 50/sin40°
  4. Evaluate:                                           x = 77.7862
  5. Round:                                              x = 77.8 ft
6 0
3 years ago
please help if you answer I will give you brainliest also you smart just please explain to me how you got the answer if you don'
EastWind [94]

Answer:

2.352

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Noel has rowing lessons every 5 days and guitar lessons every 6 days. If he had both lessons on the last day of the previous mon
bixtya [17]

Answer:

Since every 30 days  he  wil have both lessons on the same day , and  he already  had both lessons on the last day of the previous month, that means that the day 30  the current month   he  wil have both lessons on the same day (It may be the last day if the month has 30 days or it may not be the last day if the month has 31 days)

Step-by-step explanation:

Lets find the least common factor of 5 and 6

Multiples of 5

5  10  15  20  35  30  35  40......

Multiples of 6

6  12  18  24  30 36  

LCF of 5 and 6 = 30

Every 30 days  he  wil have both lessons on the same day

3 0
3 years ago
Use distributive property to simplify the expression: -4(-6p+7)
klemol [59]

Answer:

24p+ -28

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
A rectangular parking lot has a length that is 5 yards greater than the width the area of the parking lot is 300 yd.² find the l
ArbitrLikvidat [17]

Answer:

width=5yd and length=10yd

Step-by-step explanation:

To solve this problem, you need to start by asking what you do and don't know (always where to start with word problems)

We know that Area (A) = Length (L) * Width (W)

You know Area (A) = 50 sq. yds.

You don't know anything about the width, so let's just say Width (W) = x

And you know that the length is 5 yds longer than the width, so L = W + 5yd and, since W = x, we can say L = x + 5yd

Now, we recall that A = L * W, and, since A = 50, we can say 50 sq yd = L * W.

Well, now just plug in. What does W equal and L equal?

From above we plug in and can say that 50 sq yd = x * (x + 5 yd).

Multiply it out and you get 50 = x^2 + 5x (removing units for a moment so they don't clutter the lines).

Now there are a number of ways to solve this. You can tell (because of the "x^2") that it is quadratic. So let's get it equal to zero:

0 = x^2 + 5x - 50

Now you can factor it, use your quadratic formula, or (if you hated yourself) do it as a completing the square problem. I'm going to factor.

I can see from going through a list in my head that the factors 10 and -5 multiply to -50 and add to 5, so I know that

0 = x^2 + 5x - 50 = (x + 10)(x - 5)

And so you know that x = -10 or 5.

Well, you know the parking lot cannot be -10 yd long. So we must say that W = x = 5, and, since L = W + 5, then L = 5+5 = 10. So your width is 5 yd and length is 10 yd.

<h2>mark me brainlist</h2>
6 0
2 years ago
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