The Trigonometric Pythagorean Theorem is always true:
If we solve for we get
We know
so both sides are clearly between zero and one.
It's actually much better to do geometry using squared sine, but that's a topic for another day. It comes from replacing angle, a complicated directed meeting of two rays, with the intersection of two lines. Among many advantages, this eliminates quadrants.
But we know sine and cosine can be positive or negative. So we need the multivalued square root:
The means that it might be plus, it might be minus, if you just tell me the cosine there's not (usually) enough information to know which.
So yes, sometimes
That's a negative sine. If the cosine is positive, is in the fourth quadrant. If the cosine is negative, is in the third quadrant.
I'm confused by what you're saying (plz describe more thoroughly)
For this case:
D.-) The system has infinitely many solutions.
<h2>
Explanation:</h2>
Remember that you have to write complete questions in order to find exact and good answers. In this exercise, the system is missing. However, I'll provide the following system:
So we have two equations and two variables. Our first equation is:
And the second equation is:
When graphing these two lines, we can get the following possibilities:
- They have a unique solution. This means the graphs intersect at a single point.
- They have infinitely many solutions. This implies the lines are basically the same.
- They have no solution. This implies they are parallel but with different y-intersect.
By dividing equation (2) by 2 we get:
So we get the same equation as line (1), so <em>the conclusion is that they have infinitely many solutions.</em>
<h2>Learn more:</h2>
Infinitely many solutions: brainly.com/question/13771057
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