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Fiesta28 [93]
3 years ago
6

What is the first step to simplify the expression?

Mathematics
2 answers:
Snezhnost [94]3 years ago
8 0

Answer:

I believe it is the last one i'm not sure

Step-by-step explanation:


denpristay [2]3 years ago
7 0

For this case, we must show the first step to simplify the following expression:

\frac {3 (x + 8) ^ 2} {(x + 2)}

So, the first step is to solve the binomial to the square of the numerator, in the form:

(a + b) ^ 2 = a ^ 2 + 2ab + b ^ 2

So, we have:

(x + 8) ^ 2 = x ^ 2 + 2 * x * 8 + 8 ^ 2\\(x + 8) ^ 2 = x ^ 2 + 16x + 64

Then, the expression is as follows:

\frac {3 (x ^ 2 + 16x + 64)} {(x + 2)}

Answer:

Option D

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-7(2x-5)=-91<br> And I also need to do the check
ASHA 777 [7]

Answer: the answer is x=9

Step-by-step explanation:

Divide both sides by the numeric factor on the left side, then solve.

-7(2x-5)=-91

8 0
3 years ago
Read 2 more answers
What is the difference between arcsin and sin^-1 ?
Len [333]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2094473

_______________


Both refer to the inverse sine function.

The inverse sine (or arcsine) of x:

\mathsf{f(x)=arcsin(x)=sin^{-1}(x)}


where x is a real number in the domain of the function:

\mathsf{-1\le x\le 1}


and the arcsine function returns an angle in the interval  \mathsf{\left[-\,\frac{\pi}{2},\,\frac{\pi}{2}\right]:}

\mathsf{-\,\dfrac{\pi}{2}\le arcsin(x)\le \dfrac{\pi}{2}}\quad\longleftarrow\quad\textsf{range of the inverse sine function.}


So if you see anywhere one of these expressions below

\mathsf{\theta=arcsin(x)~~or~~\theta=sin^{-1}(x)}


then you should look for an angle \theta that satisfies the following conditions:

\footnotesize\begin{array}{l}\bullet\end{array}\normalsize\begin{array}{l}\mathsf{sin\,\theta=x;} \end{array}\\\\\\&#10;\footnotesize\begin{array}{l}\bullet\end{array}\normalsize\begin{array}{l}\mathsf{\dfrac{\pi}{2} \le \theta\le\dfrac{\pi}{2}.} \end{array}


This angle \theta is called the inverse sine of the real number x.

______


Pay attention and do not mistake the arcsine function for the reciprocal of sine (which is cosecant); especially if you prefer or see that notation with an superscript -1. This one can be easily mistaken for an exponent:

\mathsf{sin^{-1}(x)=arcsin(x)\qquad\quad\checkmark}


but the reciprocal is something like

\mathsf{\big[sin(x)\big]^{-1}=\dfrac{1}{sin\,(x)}=csc(x)\qquad\quad(!!)}

and this last one has a total different meaning.


I hope this helps. =)

6 0
4 years ago
In a freshman class of 80 students,22 students take Consumer Education,20 students take French,and 4 students take both.Which eq
MAXImum [283]
<h3>Answer: Choice C</h3>

P = 11/40 + 1/4 - 1/20

=========================================================

Explanation:

The formula we use is

P(A or B) = P(A) + P(B) - P(A and B)

In this case,

  • P(A) = 22/80 = 11/40 = probability of picking someone from consumer education
  • P(B) = 20/80 = 1/4 = probability of picking someone taking French
  • P(A and B) = 4/80 = 1/20 = probability of picking someone taking both classes

So,

P(A or B) = P(A) + P(B) - P(A and B)

P(A or B) = 11/40 + 1/4 - 1/20

which is why choice C is the answer

----------------

Note: P(A and B) = 1/20 which is nonzero, so events A and B are not mutually exclusive.

6 0
3 years ago
Solve the two-step equation. − 2 3 x – 21 4 = 27 4 x =
MissTica

Answer:

x = - 18

Step-by-step explanation:

Add the opposite of the constant on the left:

-2/3x = 21/4 +27/4 = 48/4 = 12

Multiply the equation by the inverse of the coefficient of x:

x = (-3/2)(12) = -18

The solution is x = - 18

5 0
3 years ago
Read 2 more answers
One number is 4 times another number. The sum of their reciprocals is 5. What are the two numbers?
ivann1987 [24]

Answer:

The two number are:

y=1,\:x=\frac{1}{4}

Step-by-step explanation:

  • Let 'x' be the first number
  • let 'y' be the second number

Given that one number is 4 times another number, the first equation is

y = 4x

Next, the sum of their reciprocals is 5, so

\frac{1}{x}+\frac{1}{y}=5

Now, we have the system of equations

\begin{bmatrix}y=4x\\ \frac{1}{x}+\frac{1}{y}=5\end{bmatrix}

Let us solve the system of equations

\begin{bmatrix}y=4x\\ \frac{1}{x}+\frac{1}{y}=5\end{bmatrix}

substitute y = 4x in the equation \frac{1}{x}+\frac{1}{y}=5

\frac{1}{x}+\frac{1}{4x}=5

Least Common Multiple of x, 4x:  4x

Adjust fractions based on L.C.M

\frac{4}{4x}+\frac{1}{4x}=5

\frac{4+1}{4x}=5

\:\frac{5}{4x}=5

Multiply both sides by 4x

\frac{5}{4x}\cdot \:4x=5\cdot \:4x

Simplify

5=20x

switch sides

20x=5

Divide both sides by 20

\frac{20x}{20}=\frac{5}{20}

Simplify

x=\frac{1}{4}

For y = 4x, substitute x=\frac{1}{4}

y = 4x

y=4\cdot \frac{1}{4}

y=1

Therefore, the two number are:

y=1,\:x=\frac{1}{4}

<u>Verification:</u>

\frac{1}{x}+\frac{1}{y}=5

substituting y=1,\:x=\frac{1}{4}

\:\frac{1}{\frac{1}{4}}+\frac{1}{1}=\:5\:\:

4+1=5

5 = 5

L.H.S = R.H.S

and

y = 4x

substituting y=1,\:x=\frac{1}{4}

y\:=\:4\left(\frac{1}{4}\right)

y=1

8 0
3 years ago
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