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marysya [2.9K]
2 years ago
13

Solve the formula Ax+By = C for A.

Mathematics
1 answer:
jok3333 [9.3K]2 years ago
8 0

Answer:

A = \frac{C - By}{x}

Step-by-step explanation:

Given

Ax + By = C

Required

Solve for A

The question implies that we make A the subject of the formula.

Start by subtracting By from both sides of the equation by x

Ax + By - By= C - By

Ax = C - By

Divide both sides by x

\frac{Ax}{x} = \frac{C - By}{x}

A = \frac{C - By}{x}

<em>Solved</em>

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Susan deposits $1,200 in an account that earns 8% simple interest annually.
spayn [35]

interest = principal x rate x time

interest = 1344-1200 = 144

principal = 1200

rate = 8% = .08

144 = 1200 x .08 x Time

Time = 1.5 yrs

3 0
3 years ago
I don’t understand this
kumpel [21]

Answer: a=x represents sinks

b=the amount of money he will spend overall on the sink and sealent

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Step-by-step explanation:

8 0
3 years ago
In ΔPQR, the measure of ∠R=90°, the measure of ∠Q=46°, and RP = 97 feet. Find the length of PQ to the nearest tenth of a foot.
Whitepunk [10]

Answer:

PQ = 134.9 feet

Step-by-step explanation:

sin 46 = 97/PQ

0.7193 = 97/PQ

PQ = 134.85 feet

5 0
3 years ago
If g(x) = 2x2 + 6x + 5, use synthetic division to find g(-5).
diamong [38]
<h3>Answer:  25</h3>

=================================================

Explanation:

Check out the image below. I've posted the synthetic division table. The value at the very end of the bottom row is the remainder. By the remainder theorem, this is exactly the value of g(-5).

Recall the remainder theorem says: If you divide p(x) by (x-k), then the remainder is p(k). In this case, k = -5 is our test root which is the value placed in the box on the left.

As a way to check the answer, we can say

g(x) = 2x^2 + 6x + 5

g(-5) = 2(-5)^2 + 6(-5) + 5

g(-5) = 25

So the answer is confirmed.

6 0
2 years ago
Is the point (1, -3) a solution to the system? Show all work
Studentka2010 [4]

Answer:

The point P(1,-3) is not a solution to the system.

Step-by-step explanation:

Given  \left \{ {{y-x+2}} \right.  

Let a point be P(1,-3)

Here x = 1 ; y = -3

Substituting the values of x,y in the function

\left \{ {{y-x+2}} \right.

For y<x-1

-3 < 1-1

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now for,

y>-x+2

-3 > -1 + 2

-3 > 1 (False)

Hence the point is not a solution to the system.

6 0
2 years ago
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