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3 years ago

9

Help?!!!I’m supposed to write a possible situation for each graph

1 answer:

telo118 [61]3 years ago

5 0

For the first one t could be a volcano that’s slowly caving in over time, and for the 2nd one it could be a store that’s selling something, and the cost per person was bigger when there was less people, but since more people came they didn’t have to charge as much ^ ^

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Which statement completes the proof that the sum of the angles of triangle PRQ is 180°? Statement Justification

vichka [17]

M∠1 + m∠RPQ + m∠5 = 180° Definition of a Straight Angle

proof : mes1= PRQ (alternate interior)

RPQ = 3 Opposite angle (vertex)
5 =Q (alternate interior)
PRQ + RPQ + RQP = 180

7 0

3 years ago

Read 2 more answers

If no number can be used more than once, how many different 2-digit numbers can be formed from the digits 4, 6, and 8?

ikadub [295]

Answer:

Six.

46

48

64

68

84

86

Step-by-step explanation:

hoped this helped!

4 0

3 years ago

Which of the following equations is equivalent to 4[x + 2(3x – 7)] = 22x – 65?

pickupchik [31]

Answer:

X= -3/2

Step-by-step explanation:

6x/6=-9/6

6 0

3 years ago

The surface area of a right circular cone of radius r and height h is S = πr√ r 2 + h 2 , and its volume is V = 1 3 πr2h. What i

kirill115 [55]

Answer:

Required largest volume is 0.407114 unit.

Step-by-step explanation:

Given surface area of a right circular cone of radious r and height h is,

$S=\pi r\sqrt{r^2+h^2}$

and volume,

$V=\frac{1}{3}\pi r^2 h$

To find the largest volume if the surface area is S=8 (say), then applying Lagranges multipliers,

$f(r,h)=\frac{1}{3}\pi r^2 h$

subject to,

$g(r,h)=\pi r\sqrt{r^2+h^2}=8\hfill (1)$

We know for maximum volume $r\neq 0$ . So let $\lambda$ be the Lagranges multipliers be such that,

$f_r=\lambda g_r$

$\implies \frac{2}{3}\pi r h=\lambda (\pi \sqrt{r^2+h^2}+\frac{\pi r^2}{\sqrt{r^2+h^2}})$

$\implies \frac{2}{3}r h= \lambda (\sqrt{r^2+h^2}+\frac{ r^2}{\sqrt{r^2+h^2}})\hfill (2)$

And,

$f_h=\lambda g_h$

$\implies \frac{1}{3}\pi r^2=\lambda \frac{\pi rh}{\sqrt{r^2+h^2}}$

$\implies \lambda=\frac{r\sqrt{r^2+h^2}}{3h}\hfill (3)$

Substitute (3) in (2) we get,

$\frac{2}{3}rh=\frac{r\sqrt{R^2+h^2}}{3h}(\sqrt{R^2+h^2+}+\frac{r^2}{\sqrt{r^2+h^2}})$

$\implies \frac{2}{3}rh=\frac{r}{3h}(2r^2+h^2)$

$\implies h^2=2r^2$

Substitute this value in (1) we get,

$\pi r\sqrt{h^2+r^2}=8$

$\implies \pi r \sqrt{2r^2+r^2}=8$

$\implies r=\sqrt{\frac{8}{\pi\sqrt{3}}}\equiv 1.21252$

Then,

$h=\sqrt{2}(1.21252)\equiv 1.71476$

Hence largest volume,

$V=\frac{1}{3}\times \pi \times\frac{\pi}{8\sqrt{3}}\times 1.71476=0.407114$

3 0

3 years ago

What is 9x6+(5x7+4x3)63x8

irina [24]

Solution:

$=9*6+(5*7+4*3)63*8\\=54+(35+12)504\\=54+47*504\\=54+23688\\=23742\\$

Answer:

$23742$

<em>Hope this was helpful.</em>

8 0

3 years ago

Read 2 more answers