Answer:
weight = 736 kg
Step-by-step explanation:
Let ball be denoted by b and box by x
Given that:
3b + x = 1840kg ----------- eq1
According to given scenario:
each ball is thrice heavy than box So,
b = 3x -------------- eq2
Putting value of b in eq1
3 (3x) + x = 1840 kg
9x + x = 1840 kg
10x = 1840 kg
Dividing both sides by 10
x = 184 kg
Now finding weight of betal ball
Putting value of x in eq 2
b = 3 (184)
b = 552 kg
So the weight of one ball and box is:
weight = ball + box
weight = 552kg + 184 kg
weight = 736 kg
i hope it will help you!
