Ask question

Ask question

All categories

3 years ago

12

Which equation describes the sum of the vectors plotted below?

1 answer:

Alex787 [66]3 years ago

8 0

Answer: $A) \ 3\vec{x} -2\vec{y}$

Step-by-step explanation:

The resultant can be calculated using triangular law of vector addition as :

$\rm \vec{r}=\vec{AB} +\vec{AC}=2x+y+x-3y=\boxed{3x-2y }$

You might be interested in

The odds of winning a teddy bear are 5:8. The probability of winning a framed picture is 43%. For which do you have a better cha

Serhud [2]

Answer:

I'd say you had a better chance going 5:8

4 0

3 years ago

The laws that established an official system of slavery in the American colonies

expeople1 [14]

<span>Good Morning!

</span><span>C)made it legal to keep enslaved people for their entire lives.
</span><span>

It was legal, for the system of slavery sustained in the British colonies - and also in the Spanish and Portuguese, as in the case of Brazil - to maintain a person as a slave throughout his life. There was no time limit, children were also enslaved - daughters of slaves.

Hugs!</span>

5 0

3 years ago

How can you find the areas of the faces of the prism

In-s [12.5K]

Answer:

The general formula for the total surface area of a right prism is T. S. A. =ph+2B where p represents the perimeter of the base, h the height of the prism and B the area of the base.

Step-by-step explanation:

give me brainliest please

5 0

3 years ago

What is the value of 3 1/2 - 9 3/4

soldi70 [24.7K]

The value or outcome would be -6.25 .

8 0

2 years ago

Read 2 more answers

A student on a piano stool rotates freely with an angular speed of 2.85 rev/s . The student holds a 1.50 kg mass in each outstre

Vlad1618 [11]

Answer:r'=0.327 m

Step-by-step explanation:

Given

$N=2.85 rev/s$

angular velocity $\omega =2\pi N=17.90 rad/s$

mass of objects $m=1.5 kg$

distance of objects from stool $r_1=0.789 m$

Combined moment of inertia of stool and student $=5.53 kg.m^2$

Now student pull off his hands so as to increase its speed to 3.60 rev/s

$\omega _2=2\pi N_2$

$\omega _2=2\pi 3.6=22.62 rad/s$

Initial moment of inertia of two masses $I_0=2mr_^2$

$I_0=2\times 1.5\times (0.789)^2=1.867$

After Pulling off hands so that r' is the distance of masses from stool

$I_0'=2\times 1.5\times (r')^2$

Conserving angular momentum

$I_1\omega =I_2\omega _2$

$(5.53+1.867)\cdot 17.90=(5.53+I_o')\cdot 22.62$

$I_0'=1.397\times 0.791$

$I_0'=5.851$

$5.53+2\times 1.5\times (r')^2=5.851$

$2\times 1.5\times (r')^2=0.321$

$r'^2=0.107009$

$r'=0.327 m$

7 0

3 years ago