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Stolb23 [73]
2 years ago
12

Which equation describes the sum of the vectors plotted below?

Mathematics
1 answer:
Alex787 [66]2 years ago
8 0

Answer: A) \   3\vec{x} -2\vec{y}  

Step-by-step explanation:

The resultant can be calculated using triangular law of vector addition as :

\rm \vec{r}=\vec{AB} +\vec{AC}=2x+y+x-3y=\boxed{3x-2y }

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Amanda is playing her new video game, Track Runner. At first, she earned 20 points for
Reika [66]

Answer: no the answer should have been -5 not 5 because Amanda lost more points than she gained

Step-by-step explanation:

20+(-25)=-5

5 0
2 years ago
There are 5 times as many yellow labs as terriers in the dog park .if there are a total of 18 dogs how many dogs are terriers?
tekilochka [14]
Let t = number of terriers
1 x t = number of total terriers
5 x t = number of yellow labs
1t + 5t = 6t
6t = total number of dogs in the park
6t = 18
t = 18/6
t = 3
there are 3 terriers
8 0
3 years ago
Nine tiles are numbered $\color[rgb]{0.35,0.35,0.35}1, 2, 3, \ldots, 9$. Each of three players randomly selects and keeps three
Eduardwww [97]

The probability that all three players obtain an odd sum is 3/14.

<h3>What is probability?</h3>

The probability is the ratio of possible distributions to the total distributions.

I.e.,

Probability = (possible distributions)/(total distributions)

<h3>Calculation:</h3>

Given that,

There are nine tiles - 1, 2, 3,...9, respectively.

A player must have an odd number of odd tiles to get an odd sum. That means he can either have three odd tiles, or two even tiles and an odd tile.

In the given nine tiles the number of odd tiles = 5 and the number of even tiles = 4.

The only possibility is that one player gets 3 odd tiles and the other two players get 2 even tiles and 1 odd tile.

So,

One player can be selected in ^3C_1  ways.

The 3 odd tiles out of 5 can be selected in ^5C_3 ways.

The remaining 2 odd tiles can be selected and distributed in ^2C_1 ways.

The remaining 4 even tiles can be equally distributed in \frac{4 ! \cdot 2 !}{(2 !)^{2} \cdot 2 !} ways.

So, the possible distributions = ^3C_1 × ^5C_3 × ^2C_1 × \frac{4 ! \cdot 2 !}{(2 !)^{2} \cdot 2 !}

⇒ 3 × 10 × 2 × 6 = 360

To find the total distributions,

The first player needs 3 tiles from the 9 tiles in ^9C3=84 ways

The second player needs 3 tiles from the remaining 6 tiles in ^6C_3=20 ways

The third player takes the remaining tiles in 1 way.

So, the total distributions = 84 × 20 × 1 = 1680

Therefore, the required probability = (possible distributions)/(total distributions)

⇒ Probability = 360/1680 = 3/14.

So, the required probability for the three players to obtain an odd sum is 3/14.

Learn more about the probability of distributions here:

brainly.com/question/2500166

#SPJ4

3 0
1 year ago
Give two points with integer coordinates that have a slope of 10/7 between them
Fittoniya [83]

Answer:

(0,0) and (7,10)

Step-by-step explanation:

recall that the slope - intercept  form of a linear equation can be given as

y = mx + b

where m = slope and b = y intercept

in our case, we are given that slope, m = 10/7, hence our equation becomes

y = (10/7) x + b

since we are not given any information about the y-intercept, we can simply pick a value for b that is most convenient for us.

We pick b = 0, hence the equation simplifies to:

y = (10/7) x  ----- eq 1

we can see immediately that if x = 0, y must also = 0

proof if x = 0:

y = (10/7)(0) =0

since 0 is an integer, then (0,0) must be the first point.

we can also observe that for y to be an integer, we must get rid of the denominator 7. We can do this by multiply the right side by 7. Hence we let x = 7:

y = (10/7) x 7

y = 10

hence (7,10) is the second point.

7 0
3 years ago
26. A single card is drawn from a deck. Find the probability that the card is either red or a face card.
Lana71 [14]

Answer:

8/13

Step-by-step explanation:

There are total 26 red cards in the deck of 52 cards.

There are also 12 face cards in the deck ( which is 6 of them are red, while 6 of them are black)

Since we only need either one of them, 26 + 6 = 32

The probability of drawn a card that either red or a face card is 32/52

The simplest form of this fraction is 8/13.

7 0
1 year ago
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