6 is in the ones place
.5 is in the tenths place
and the 4 in 6.54 is in the hundredths place
Answer:
84 sq meters
Step-by-step explanation:
1. Approach
In order to solve this problem, one will have to divide the figure up into simple shapes. A picture is attached showing how the shape is divided up for this answer. Find the area of each region, then add up the results to find the total area.
2. Area of Region 1
As one can see, the length of (Region 1), as given is (6), the width is (3). To find the area multiply the length by the width.
Length * width
6 * 3
= 18
3. Area of Region 2
In (Region 2), the length is given, (12). However, one must find the width, this would be the size of the total side, minus the width of (Region 1). Multiply the length by the side to find the area.
Length * width
= 12 * (8 - 3)
= 12 * 5
= 60
4. Area of Region 3
In (Region 3), the length of the figure is (2), the width is (3). To find the area, multiply the length by the width.
Length * width
= 2 * 3
= 6
5. Total area
Now add up the area of each region to find the total rea,
(Region 1) + (Region 2) + ( Region 3)
= 18 + 60 + 6
= 84
This is true.
When we're talking about the mode, we're usually talking about the number which has the highest frequency in a given set of numbers. For example, out of the numbers:
1 2 3 4 5 6 5 4 5 5 5
5 will be the mode.
Answer:
54y² +255y +300
Step-by-step explanation:
Such an expression is simplified by eliminating parentheses and combining like terms.
<h3>Eliminate parentheses</h3>
Taking the given expression at face value, we have ...
{2(3y+6)-3(-4-y)}2(3y+6)−3(−4−y)
= {6y +12 +12 +3y}(6y +12) +12 +3y
= (9y +24)(6y +12) +12 +3y
= (9y)(6y +12) +24(6y +12) +12 +3y
= 54y² +108y +144y +288 +12 +3y
<h3>Combine like terms</h3>
= 54y² +(108 +144 +3)y +(288 +12)
= 54y² +255y +300
The answer simplified is:
a= —2x^2+7x+22