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avanturin [10]
3 years ago
5

Help with these questions immediately

Mathematics
1 answer:
alisha [4.7K]3 years ago
3 0

Problem 1

<h3>Answer: Choice C)  1/2</h3>

--------------------

Explanation:

Let's plug 8 into f(x)

f(x) = \frac{x+3}{x^2-4x-21}\\\\f(8) = \frac{8+3}{8^2-4(8)-21}\\\\f(8) = \frac{8+3}{64-32-21}\\\\f(8) = \frac{11}{11}\\\\f(8) = 1\\\\

Repeat for g(x)

g(x) = \log_{4}(x)\\\\g(8) = \log_{4}(8)\\\\g(8) = \frac{\log(8)}{\log(4)}\\\\g(8) = \frac{\log(2^3)}{\log(2^2)}\\\\g(8) = \frac{3*\log(2)}{2*\log(2)}\\\\g(8) = \frac{3}{2}\\\\

I used the change of base formula in the third step.

Lastly, we subtract the results like so

(g-f)(x) = g(x) - f(x)\\\\(g-f)(8) = g(8) - f(8)\\\\(g-f)(8) = \frac{3}{2} - 1\\\\(g-f)(8) = \frac{3}{2} - \frac{2}{2}\\\\(g-f)(8) = \frac{3-2}{2}\\\\(g-f)(8) = \frac{1}{2}\\\\

========================================================

Problem 2

<h3>Answer: Choice A)  8</h3>

--------------------

Explanation:

Through trial and error (I recommend the rational root theorem), you should find that the roots of R(x) are:  -1, 3, and 8

We'll only focus on positive x values. So we focus on the roots 3 and 8.

It turns out that the R(x) curve dips below the x axis when x is between 3 and 8. When x > 8 is when R(x) is positive and goes upward forever. This represents when the company is making money.

The company does make money when x is between 0 and 3; however, this is a short timespan compared to the other interval. So it's much more effective and realistic to say that the company makes money after 8 days.

In other words, yes the company makes money between day 0 and day 3, but from day 3 to day 8 is when the company loses money. Ultimately the company is profitable again when it's beyond day 8.

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zhuklara [117]

Step-by-step answer:

Given:

A triangle

Perimeter  = 60 cm

longest side = 4* shortest side (x)

Solution:

longest side = 4x

shortest side = x

third (intermediate side = 60 -x -4x = 60-5x

The triangle inequality specifies that the sum of the two shorter sides must be greater than the longest side to form a triangle.  Hence

x + y > 4x

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x < 60/8 = 7.5, or

x < 7.5

Therefore to form a triangle, x (shortest side) must be less than 7.5 cm.

Examine the options: both 7 and 5 are both less than 7.5 cm.

40, 30 and 25 all have a problem because the longest side (4 times longer) will exceed the perimeter of 60.

Now also examine cases where 4x is NOT the longest side, in which case we need

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or

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9x >=60

x >= 6.67

so x=5 will not qualify, because 4x will no longer be the longest side.

The only valid option is x=7 cm

The side lengths for x=7 and x=5 are, respectively,

(7, 25, 28)

5, 20, 35  (in which case, the longest side is no longer 4x=20, so eliminated)

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