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borishaifa [10]
3 years ago
5

5 more than 3 times a variable, x, is 23

Mathematics
1 answer:
Monica [59]3 years ago
5 0

3x + 5 = 23

5 more than(addition) 3 times(multiplication) a variable(x) is(equals) 23

(you add 5 to 3x)

If you need to solve for "x", you need to isolate/get the variable "x" by itself in the equation:

3x + 5 = 23        Subtract 5 on both sides

3x + 5 - 5 = 23 - 5

3x = 18      Divide 3 on both sides to get "x" by itself

\frac{3x}{3} =\frac{18}{3}

x = 6

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scoray [572]
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3 years ago
A young couple purchases their first new home in 2011 for​ $95,000. They sell it to move into a bigger home in 2018 for​ $105,00
mart [117]

Given:

The value of home in 2011 is $95,000.

The value of home in 2018 is $105,000.

To find:

The exponential model for the value of the home.

Solution:

The general exponential model is

y=ab^x       ...(i)

where, a is initial value and b is growth factor.

Let 2011 is initial year and x be the number of years after 2011.

So, initial value of home is 95,000, i.e., a=95,000.

Put a=95000 in (i).

y=95000b^x       ...(ii)

The value of home in 2018 is $105,000. It means the value of y is 105000 at x=7.

105000=95000b^7

\dfrac{105000}{95000}=b^7

\dfrac{21}{19}=b^7

Taking 7th root on both sides, we get

\left(\dfrac{21}{19}\right)^{\frac{1}{7}}=b

Put b=\left(\dfrac{21}{19}\right)^{\frac{1}{7}} in (ii).

y=95000\left(\left(\dfrac{21}{19}\right)^{\frac{1}{7}}\right)^x

y=95000\left(\dfrac{21}{19}\right)^{\frac{x}{7}}

Therefore, the required exponential model for the value of home is y=95000\left(\dfrac{21}{19}\right)^{\frac{x}{7}}, where x is the number of years after 2011.

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dimaraw [331]
A secant line always contains a chord.
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