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UNO [17]
4 years ago
14

Can someone please help me with this queston? I've been stuck on it forever.

Mathematics
1 answer:
Marrrta [24]4 years ago
6 0
You have two rectangular sides with a total area of:

A=2(10*15)=300 ft^2

You have two triangular sides with a total area of:

A=2(8*12)/2=96 ft^2

And you have a rectangular base with an area of:

A=15*12=180 ft^2

So the total surface area is:

A=300+96+180=576 ft^2
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Is it correct ?
CaHeK987 [17]

Answer:

Step-by-step explanation:

It is correct till 16/15

But after that it is 16/15 × 5/-3 = 80/-45

simplify it to 16/-9

6 0
2 years ago
What type of fault occurs when plates move past each other in opposite directions? transform fault reverse fault strike-slip fau
statuscvo [17]

Answer:

strike-slip fault

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
A small rectangular tissue box is 0.5 feet long, 0.2 feet wide, and 0.3 feet deep. The box is filled completely with tissues
Verizon [17]

Answer:

the volume of the tissue box would be 0.2×0.5×0.3. the volume of a rectangular prisim is V=l×w×h

6 0
3 years ago
Work out the surface area of this cylinder.<br><br> Please help, I will award brainliest.
gogolik [260]

Answer:

8*16.8 which is 302.4

Step-by-step explanation:

8 0
3 years ago
Write the equation of a hyperbola with vertices at (1,1) and (9, 1) and foci at (0, 1) and (10, 1).
Leni [432]

Answer:

Standard form of equation for a hyperbola with horizontal transverse axis:

(x-h)^2/a^2-(y-k)^2/b^2=1, (h,k)=(x,y) coordinates of center

For given hyperbola:

x-coordinate of center=(9+1)/2=5 (use midpoint formula)

y-coordinate of center=1

center: (5,1)

length of horizontal transverse axis=8 (from 1 to 9)=2a

a=4

 

a^2=16

..

Foci

2c=9 ( from 1 to 10)

c=4.5

..

c^2=a^2+b^2

b^2=c^2-a^2=20.25-16=4.25

..

Equation of hyperbola:

(x-5)^2/16-(y-1)^2/4.25=1

7 0
4 years ago
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