3 years ago

Can someone please tell me if any of my answers are wrong!????

1 answer:

5 0

Couldn’t quite read everything, the writing is very light. But from what I could read, it was correct for the most part. :)

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Step 1 choices:

Julli [10]

You have to translate the triangle over to where point B is lined up with point B in the second triangle. Then you can reflect over the y-axis.
So...your answer should be...
Step 1:A.
Step 2:C.

6 0

3 years ago

Read 2 more answers

Find the perimeter and area of a rectangle with a width of 2 feet and a length 3 times as long.

rusak2 [61]

Answer:

Length = Width * 3

Width = 2 ft

Length = 2 ft * 3 = 6 ft

Perimeter = (L * 2) + (W * 2)

P = 16 ft

Area = L * W = 12 square feet

5 0

3 years ago

Read 2 more answers

There are the two photos to solve it and jus write A B or C please

Sidana [21]

The answer would be B

8 0

3 years ago

(8 ^ 4 * 9 ^ 5)/(16 ^ 2 * 27 ^ 3)<br>help needed plzzzzzz helppppp

Roman55 [17]

Answer:

answer is 48

Step-by-step explanation:

simplified after exponents.

4,096 x 59,049/ 256 x 19,683

simplified after multipled

241,864,704/5,038,848

= 48

6 0

3 years ago

The width of a rectangle is the length minus 2 units. the area of the rectangle is 35 units

Mariana [72]

Answer:

$Length=7units\\\\Width=5units$

Step-by-step explanation:

Width=(Length-2) units

W=(L-2) units

Area of the rectangle= 35 square units

Area = length* Width

$35= L*(L-2)\\\\35=L^2-2L$

Subtracting 35 both sides:

$L^2-2L-35=0$

Solving the quadratic equation for 'L' ;

Using factorization:

$L^2+5L-7L-35=0$

Taking common from the equation :

$L(L+5)-7(L+5)=0\\\\(L+5)(L-7)=0\\\\L+5=0\\\\L=-5$

$L-7=0\\\\L=7$

The length cannot be negative, therefore Length(L)= 7

$Width=Length-2\\\\=7-2\\\\=5 units$

$Length=7units\\\\Width=5units$

8 0

3 years ago