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Zolol [24]
3 years ago
11

Evaluate the expression (x - y)^2 – x when x=3 and y=8 HELP PLEASE‼️‼️

Mathematics
2 answers:
vovikov84 [41]3 years ago
3 0

Answer:

22

Step-by-step explanation:

Step 1: fill in the equation

(3-8)^2-3

Step 2: simplify

= -5^2-3

= 25-3

Step 3: solve

= 22

Doss [256]3 years ago
3 0

Answer:

This would change into (9 - 64) - 3 which would change to, -55 - 3 = -58

Step-by-step explanation:

Hope this helped!

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Find the difference: 101100012 - 11011012. Express your answer as a Base<br> 2 number.
Marizza181 [45]

Answer:

<h2>The answer is 1000100</h2>

Step-by-step explanation:

10110001 - 1101101 = 1000100

Hope this helps you

7 0
2 years ago
Find the probability that a randomly generated bit string of length 10 does not contain a 0 if bits are independent and if:a) a
lara31 [8.8K]

Answer:

A) 0.0009765625

B) 0.0060466176

C) 2.7756 x 10^(-17)

Step-by-step explanation:

A) This problem follows a binomial distribution. The number of successes among a fixed number of trials is; n = 10

If a 0 bit and 1 bit are equally likely, then the probability to select in 1 bit is; p = 1/2 = 0.5

Now the definition of binomial probability is given by;

P(K = x) = C(n, k)•p^(k)•(1 - p)^(n - k)

Now, we want the definition of this probability at k = 10.

Thus;

P(x = 10) = C(10,10)•0.5^(10)•(1 - 0.5)^(10 - 10)

P(x = 10) = 0.0009765625

B) here we are given that p = 0.6 while n remains 10 and k = 10

Thus;

P(x = 10) = C(10,10)•0.6^(10)•(1 - 0.6)^(10 - 10)

P(x=10) = 0.0060466176

C) we are given that;

P((x_i) = 1) = 1/(2^(i))

Where i = 1,2,3.....,n

Now, the probability for the different bits is independent, so we can use multiplication rule for independent events which gives;

P(x = 10) = P((x_1) = 1)•P((x_2) = 1)•P((x_3) = 1)••P((x_4) = 1)•P((x_5) = 1)•P((x_6) = 1)•P((x_7) = 1)•P((x_8) = 1)•P((x_9) = 1)•P((x_10) = 1)

This gives;

P(x = 10) = [1/(2^(1))]•[1/(2^(2))]•[1/(2^(3))]•[1/(2^(4))]....•[1/(2^(10))]

This gives;

P(x = 10) = [1/(2^(55))]

P(x = 10) = 2.7756 x 10^(-17)

3 0
3 years ago
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lina2011 [118]

The answer is D. Dual enrollment courses

5 0
2 years ago
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At a car garage there are 100 vehicles, 60 of which are cars, 30 are vans and the remainder are
zhannawk [14.2K]

Answer:

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Step-by-step explanation:

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