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3 years ago

Describe the transformations of the quadratic function y=-x^2+3

Mathematics

1 answer:

svetlana [45]3 years ago

4 0

Answer:

translate parabola left three units.

Step-by-step explanation:

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1. Use a ratio box to solve this problem. Tammy saved nickels and

Mice21 [21]

Answer:

245

Step-by-step explanation:

let 'c' = total coins

2/7 = 70/c

2c = 490

c = 245

7 0

3 years ago

What is the standard form of 5.93-5

vredina [299]

Just subtract the whole numbers, 5.93-5 = 0.93.

4 0

3 years ago

Does anyone know how to do this?? steps are helpful but not necessary

aniked [119]

Answer:

C. $\frac{2(x+16)}{x+4}$

Step-by-step explanation:

We want fg of x, so first we have to multiply f(x) times g(x).

$\frac{x+16}{x} * \frac{2x}{x+4}$

$\frac{(x+16)2x}{x(x+4)}$

$\frac{2x^{2}+32x}{x^{2}+4x}$

We can cancel out an x from every term.

$\frac{2x+32}{x+4}$

Let's rewind a little to get this into one of the answer choices.

$\frac{2(x+16)}{x+4}$ is our answer.

6 0

3 years ago

Find the difference between8/15 and 2/3 Show all calculations in your final answer.

kherson [118]

Answer:

$\frac{8}{15}-\left(\frac{-2}{3}\right)=\frac{6}{5}$

Step-by-step explanation:

Let the value of a number 'a' be = 8/15

Let the value of a number 'b' be = 2/3

The difference between the two numbers can be calculated by subtracting the numbers

$a-b=\frac{8}{15}-\left(\frac{-2}{3}\right)$

$\mathrm{Remove\:parentheses}:\quad \left(a\right)=a$

$=\frac{8}{15}-\frac{-2}{3}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{b}=-\frac{a}{b}$

$=\frac{8}{15}-\left(-\frac{2}{3}\right)$

$\mathrm{Apply\:rule}\:-\left(-a\right)=a$

$=\frac{8}{15}+\frac{2}{3}$

$\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}$

$=\frac{8+10}{15}$

$=\frac{18}{15}$

$\mathrm{Cancel\:the\:common\:factor:}\:3$

$=\frac{6}{5}$

Thus,

$\frac{8}{15}-\left(\frac{-2}{3}\right)=\frac{6}{5}$

3 0

3 years ago

Given the system of equations, what is the solution?

fredd [130]

The solution for the given equations x + 3y = 5 and x - 3y = -1 are x=2 and y=1.

Step-by-step explanation:

The given is,

$x+3y=5$ ......................................(1)

$x-3y=-1$ ....................................(2)

Step:1

By elimination method,

Subtracting Equations (1) and (2),

$x+3y=5$

$x-3y=-1$

( - )

( $x-x$ ) + ( $3y+3y$ ) = ( $5 +1$ )

$6y$ = 6

$y$ = 1

Step:2

Substitute the value of y in equation (1),

$x+3y=5$

$x$ + ( 3 × 1 ) = 5

$x$ = 5-3

$x$ = 2

Step:3

Check for Solution,

Substitute the values of x and y in Eqn (1),

$x+3y=5$

2 + ( 3 × 1 ) = 5

5 = 5

Result:

The solution for the given equations x + 3y = 5 and x - 3y = -1 are x=2 and y=1, by elimination method.

7 0

3 years ago