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denis-greek [22]
3 years ago
9

Describe the transformations of the quadratic function y=-x^2+3

Mathematics
1 answer:
svetlana [45]3 years ago
4 0

Answer:

translate parabola left three units.

Step-by-step explanation:

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1. Use a ratio box to solve this problem. Tammy saved nickels and
Mice21 [21]

Answer:

245

Step-by-step explanation:

let 'c' = total coins

2/7 = 70/c

2c = 490

c = 245

7 0
3 years ago
What is the standard form of 5.93-5
vredina [299]
Just subtract the whole numbers, 5.93-5 = 0.93.
4 0
3 years ago
Does anyone know how to do this?? steps are helpful but not necessary
aniked [119]

Answer:

C.  \frac{2(x+16)}{x+4}

Step-by-step explanation:

We want fg of x, so first we have to multiply f(x) times g(x).

\frac{x+16}{x} * \frac{2x}{x+4}

\frac{(x+16)2x}{x(x+4)}

\frac{2x^{2}+32x}{x^{2}+4x}

We can cancel out an x from every term.

\frac{2x+32}{x+4}

Let's rewind a little to get this into one of the answer choices.

\frac{2(x+16)}{x+4} is our answer.

6 0
3 years ago
Find the difference between8/15 and 2/3 Show all calculations in your final answer.
kherson [118]

Answer:

  • \frac{8}{15}-\left(\frac{-2}{3}\right)=\frac{6}{5}          

Step-by-step explanation:

  • Let the value of a number 'a' be = 8/15
  • Let the value of a number 'b' be = 2/3

The difference between the two numbers can be calculated by subtracting the numbers

a-b=\frac{8}{15}-\left(\frac{-2}{3}\right)

\mathrm{Remove\:parentheses}:\quad \left(a\right)=a

         =\frac{8}{15}-\frac{-2}{3}

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{b}=-\frac{a}{b}

          =\frac{8}{15}-\left(-\frac{2}{3}\right)

\mathrm{Apply\:rule}\:-\left(-a\right)=a

          =\frac{8}{15}+\frac{2}{3}

\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}

          =\frac{8+10}{15}

          =\frac{18}{15}

\mathrm{Cancel\:the\:common\:factor:}\:3

           =\frac{6}{5}

Thus,

  • \frac{8}{15}-\left(\frac{-2}{3}\right)=\frac{6}{5}                    
3 0
3 years ago
Given the system of equations, what is the solution?
fredd [130]

The solution for the given equations  x + 3y = 5 and x - 3y = -1 are x=2 and y=1.

Step-by-step explanation:

The given is,

           x+3y=5......................................(1)

           x-3y=-1....................................(2)

Step:1

         By elimination method,

        Subtracting Equations (1) and (2),

                     x+3y=5

                     x-3y=-1

             ( - )

           ( x-x ) + ( 3y+3y ) = ( 5 +1 )

                                       6y = 6

                                         y = 1

Step:2

        Substitute the value of y in equation (1),

                             x+3y=5

                       x + ( 3 × 1 ) = 5

                                      x = 5-3

                                      x = 2

Step:3

        Check for Solution,

        Substitute the values of x and y in Eqn (1),

                                  x+3y=5

                           2 + ( 3 × 1 ) = 5

                                         5 = 5

Result:

       The solution for the given equations  x + 3y = 5 and x - 3y = -1 are x=2 and y=1, by elimination method.

7 0
3 years ago
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