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Rainbow [258]
4 years ago
14

Combine like terms to make an expression with fewer characters. 3(x+4)-2(x+4) *

Mathematics
1 answer:
Kipish [7]4 years ago
7 0

Answer:

X+4

Step-by-step explanation:

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Can you answer this question?​
Debora [2.8K]

Answer: y= 3 times 2 to the power x. Second answer

Step-by-step explanation:

if you plug in 0 for x, y= 3x 1= 3

if you plug in 1 for x y= 3 x 2 = 6

Look at the x values and y values

(0,3) and (1, 6) on the graph. It matches answer number 2. Remember, 2 raised to the power 0 = 1 and 3 times 1 = 3. And 2 raised to the power 1 =2 and 3 times 2 = 6.

3 0
2 years ago
Please help solve this
White raven [17]

Answer:

BC~=AD (GIVEN )

CBA=CDA (altanate angles BC=AD)

C=A (altanate angles (BC=AD)

AAS

brainyliest please

8 0
3 years ago
The most common form of color blindness is an inability to distinguish red from green. However, this particular form of color bl
Alecsey [184]

Answer:

(a) The correct answer is P (CBM) = 0.79.

(b) The probability of selecting an American female who is not red-green color-blind is 0.996.

(c) The probability that neither are red-green color-blind is 0.9263.

(d) The probability that at least one of them is red-green color-blind is 0.0737.

Step-by-step explanation:

The variables CBM and CBW are denoted as the events that an American man or an American woman is colorblind, respectively.

It is provided that 79% of men and 0.4% of women are colorblind, i.e.

P (CBM) = 0.79

P (CBW) = 0.004

(a)

The probability of selecting an American male who is red-green color-blind is, 0.79.

Thus, the correct answer is P (CBM) = 0.79.

(b)

The probability of the complement of an event is the probability of that event not happening.

Then,

P(not CBW) = 1 - P(CBW)

                   = 1 - 0.004

                   = 0.996.

Thus, the probability of selecting an American female who is not red-green color-blind is 0.996.

(c)

The probability the woman is not colorblind is 0.996.

The probability that the man is  not color- blind is,

P(not CBM) = 1 - P(CBM)

                   = 1 - 0.004  

                   = 0.93.

The man and woman are selected independently.

Compute the probability that neither are red-green color-blind as follows:

P(\text{Neither is Colorblind}) = P(\text{not CBM}) \times  P(\text{not CBW})\\ = 0.93 \times  0.996 \\= 0.92628\\\approx 0.9263

Thus, the probability that neither are red-green color-blind is 0.9263.

(d)

It is provided that a one man and one woman are selected at random.

The event that “At least one is colorblind” is the complement of part (d) that “Neither is  Colorblind.”

Compute the probability that at least one of them is red-green color-blind as follows:

P (\text{At least one is Colorblind}) = 1 - P (\text{Neither is Colorblind})\\ = 1 - 0.9263 \\= 0.0737

Thus, the probability that at least one of them is red-green color-blind is 0.0737.

6 0
3 years ago
Help so i can finis this already
sveticcg [70]

Answer:

its microwave

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Twice a number divid by 6 is 42
il63 [147K]
A number=x

2x/6=42
2x=252 by multiplying both sides by 6
x=126 by dividing both sides by 2 to isolate the variable
8 0
3 years ago
Read 2 more answers
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