Answer:
-3+2sqrt7
-3-2sqrt7
Step-by-step explanation:
x^2+6x-9=10
x^2+6x-9-10=0
x^2+6x-19=0
ax^2+bx+c=0
a=1 b=6 c=-19
As cannot be solved by completing square we will use quadratic equation
x= (-b+sqrt(b^2-4ac))/2a and x= (-b-sqrt(b^2-4ac))/2a
x= (-6+sqrt(6^2-4*-19))/2 and x= (-6-sqrt(6^2-4*-19))/2
x=(-6+sqrt(36+76))/2 and x=(-6-sqrt(36+76))/2
x=(-6+4sqrt7)/2 and x=(-6-4sqrt7)/2
x=(-3+2sqrt7) and x=(-3-2sqrt7)
x=2.29 and x= -8.29
So all you need to do if find the min of the function:
f(x)=0.04x^3-4x^2-176x
f'(x)=0.12x^2-8x-176
The only zero for this is x=84.105 <---first
Plug this into f(x) to get f(84.105)=-19300 <---second
The y intercept is the value of y when x=0. Substituting we get
y = 4
Answer: 4
So the first thing you want to do when faced with two fractions with different denominators (when subtracting or adding) is to make the denominators the same. So for this equation they would turn out to be p+10/16=15/16 (because 16 is the lowest common denominator, 8 times two) so then you want to subtract 10/16 from 15/16 to isolate the variable (p) which would get:
p=5/16
This is the final answer because it cannot be simplified.
Hope this helps!
Length of the room is 5 m and width is 5 + 2 = 7 m.
Hope this helps.
r3t40
