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WITCHER [35]
2 years ago
13

Y = -2x + 2 y = 5x + 9​

Mathematics
1 answer:
WITCHER [35]2 years ago
8 0
X=-1 y=4 hope it helps
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klasskru [66]

Answer: 16.13

Step-by-step explanation: 40 divided by $2.48

5 0
3 years ago
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Please answer this it’s very hard for me
Nimfa-mama [501]

Answer:

C, D, E, F

Step-by-step explanation:

Remember y=mxb?

m is slope and b is y-intercept

so y=2/7x-9

Remember that slope is RISE/RUN so for every 2 squares that you go up, you go 7 squares to the right.

Also remember that since your graph is going thru your Cartiesian Plane in quadrent 4, your y value in your ordered pairs will most probably be a negative.

Please see the image to help you viualize this.

3 0
2 years ago
For about $1 billion in new space shuttle expenditures, NASA has proposed to install new heat pumps, power heads, heat exchanger
11111nata11111 [884]

Answer:

The probability of one or more catastrophes in:

(1) Two mission is 0.0166.

(2) Five mission is 0.0410.

(3) Ten mission is 0.0803.

(4) Fifty mission is 0.3419.

Step-by-step explanation:

Let <em>X</em> = number of catastrophes in the missions.

The probability of a catastrophe in a mission is, P (X) = p=\frac{1}{120}.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X </em>is:

P(X=x)={n\choose x}\frac{1}{120}^{x}(1-\frac{1}{120})^{n-x};\x=0,1,2,3...

In this case we need to compute the probability of 1 or more than 1 catastrophes in <em>n</em> missions.

Then the value of P (X ≥ 1) is:

P (X ≥ 1) = 1 - P (X < 1)

             = 1 - P (X = 0)

             =1-{n\choose 0}\frac{1}{120}^{0}(1-\frac{1}{120})^{n-0}\\=1-(1\times1\times(1-\frac{1}{120})^{n-0})\\=1-(1-\frac{1}{120})^{n-0}

(1)

Compute the compute the probability of 1 or more than 1 catastrophes in 2 missions as follows:

P(X\geq 1)=1-(1-\frac{1}{120})^{2-0}=1-0.9834=0.0166

(2)

Compute the compute the probability of 1 or more than 1 catastrophes in 5 missions as follows:

P(X\geq 1)=1-(1-\frac{1}{120})^{5-0}=1-0.9590=0.0410

(3)

Compute the compute the probability of 1 or more than 1 catastrophes in 10 missions as follows:

P(X\geq 1)=1-(1-\frac{1}{120})^{10-0}=1-0.9197=0.0803

(4)

Compute the compute the probability of 1 or more than 1 catastrophes in 50 missions as follows:

P(X\geq 1)=1-(1-\frac{1}{120})^{50-0}=1-0.6581=0.3419

6 0
3 years ago
Find the length of the curve y=3x^3/2 from x=0 to x=5/9
Alekssandra [29.7K]
y=3x^{3/2}\implies y'=\dfrac92x^{1/2}

The length of the curve is

L=\displaystyle\int_0^{5/9}\sqrt{1+\left(\dfrac92x^{1/2}\right)^2}\,\mathrm dx=\int_0^{5/9}\sqrt{1+\dfrac{81}4x}\,\mathrm dx=\dfrac{335}{243}
4 0
2 years ago
HELPPP pleasssse and thankssssss
Fynjy0 [20]

Answer:

VW=4

Step-by-step explanation:

UW=VW+UV

5x-5=(x)+(3x-1)

5x-5=4x-1

5x-4x=-1+5

x=4

VW=x= 4

I hope I helped you^_^

4 0
2 years ago
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