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Murrr4er [49]
3 years ago
14

Find the degree of the monomial 8ab^3

Mathematics
2 answers:
creativ13 [48]3 years ago
8 0

Answer:

B: 4

Step-by-step explanation:

#first

lubasha [3.4K]3 years ago
4 0

Answer:

A, 3

Step-by-step explanation:

The degree, otherwise known as the power, is 3.

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How would you answer the second question?
morpeh [17]
The same column vector but positiv (5/4)
5 0
3 years ago
Find all solutions in the interval from [0,2pi)<br> 2cos(3x)= -sqrt{2}
algol [13]

Solutions of 2cos(3x)= -\sqrt{2} in the interval from [0,2pi) is x =\frac{\pi}{12}  and x = \frac{23\pi}{12} .

<u>Step-by-step explanation:</u>

Find all solutions in the interval from [0,2pi)

2cos(3x)= -\sqrt{2}

⇒ 2cos(3x)= -\sqrt{2}

⇒ \frac{2cos(3x)}{2}= \frac{-\sqrt{2}}{2}

⇒ cos3x= \frac{-\sqrt{2}(\sqrt{2})}{2{\sqrt{2}}}

⇒ cos3x= \frac{-2}{2{\sqrt{2}}}

⇒ cos3x= \frac{-1}{{\sqrt{2}}}

⇒ cos^{-1}(cos3x)= cos^{-1}(\frac{-1}{{\sqrt{2}}})

⇒ 3x=\pm \frac{\pi}{4}

⇒ x=\pm \frac{\pi}{12}

Cosine General solution is :

x = \pm cos^{-1}(y)+ 2k\pi

⇒ x = \pm \frac{\pi}{12}+ 2k\pi , k is any integer .

At k=0,

⇒ x =\frac{\pi}{12} ,

At k=1,

⇒ x = - \frac{\pi}{12}+ 2\pi

⇒ x = \frac{23\pi}{12}

Therefore , Solutions of 2cos(3x)= -\sqrt{2} in the interval from [0,2pi) is x =\frac{\pi}{12}  and x = \frac{23\pi}{12} .

5 0
3 years ago
Suppose you know that ∠S and ∠Y are complementary, and that m∠S = 4(m∠Y) − 210°. Find m∠Y.
EleoNora [17]

Answer:

angle Y= 60 degrees

Step-by-step explanation:

angle S + angle Y = 90 degrees because they are complementary

Y = 90 - S

angle S = 4(Y)-210

substitute for Y

S = 4(90 - S) - 210

S = 360 - 4S - 210

reduce

5S = 150

S = 30

Y = 90 - 30 = 60

4 0
3 years ago
Can someone tell me if my answers are right? Thank you
MakcuM [25]
Awesome job its all correct! 100%

Learn on!
7 0
3 years ago
Determine if (3, 7) is a Solution or not Solution to the linear system.
spayn [35]

Answer:

y = 2x + 1 --> linear

y = -4x + 7 --> non-linear

Not a solution for linear system.

Step-by-step explanation:

for (a), y = 2x+1, substitute the x and y values. keep in mind, that in a linear pair, (x, y). So, for the first equation you get:

7 = 2x3 + 1. This is correct, because 6 + 1 is 7. Therefore, (a) is linear.

for (b), we have to substitute our values again. You get:

7 = -4x3 + 7, which is

7 = -12+7, which is not true. So, (b) is not linear.

This means that for the linear pair (3, 7), it does not satisfy both equations, which means that it is not a solution for the linear system.

7 0
3 years ago
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