Question

Find the median, lower quartile, and upper quartile for the set of data.

Answer 1

$\text{Find the median:}\\\\\text{To find the median, you would cross out the numbers from the side}\\\text{until you're left with the remainders. Put them in order and solve}\\\\1, 2, 4 ,5, 6, 7, 8, 9, 10, 11\\\text{Add 6 and 7 then divide by 2}\\\\6+7=13\\\\11\div2=6.5\\\\\boxed{\text{The median is 6.5}\\}\\\\\text{The lower quartile is the median of the numbers less than the median, so}\\\text{the numbers from 1-6}\\\\\text{When you cross out the numbers, you would be left with 4}$

$\boxed{\text{The lower quartile is 4}}\\\\\text{Do the same for the upper quartile for the numbers greater than half}\\\text{of the data set}\\\\\boxed{\text{Your upper quartile would be 9}}$

Answer 2

Answer:

Median= 6.5

lower quartile=4

upper quartile=9

Step-by-step explanation:

Order first: 1,2,4,5,6,7,8,9,10,11

Median= 6+7=13 and 13/2=6.5 (the middle number of the entire set, if two are in the middle then add both of the number and divide by 2)

lower quartile= 1,2,4,5,6... 4 (middle number of first half)

upper quartile=7,8,9,10,11...9 (middle number of second half)