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Katen [24]
3 years ago
13

Find the 5th (not fourth) of given geometric sequence. 2000, 1000, 500,...

Mathematics
1 answer:
Greeley [361]3 years ago
8 0

Answer:

125

Step-by-step explanation:

To find the common ratio, take the second term and divide by the first term

1000/2000 = 1/2

We multiply each term by 1/2

2000, 1000, 500

To find the next term 500*1/2 = 500/2 = 250

To find the 5th term

250*1/2 = 125

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The average of four numbers is 38, and the average of the first two numbers is 42, and the average of the last three numbers is
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Answer:

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Step-by-step explanation:

let the numbers be a+b+c+d.

the average of 4 numbers is 38

; (a+b+c+d)/4 = 38

(a+b+c+d) = 152 ......equ1

the average of the first two numbers is 42

; (a+b)/2 = 42

(a+b) = 84 ...... equ2

the average of the last three numbers is 36

; (b+c+d)/3 = 36

(b+c+d) = 108 .....equ3

substitute equ3 into equ1

a + 108 = 152

a= 152 - 108

a = 44

input the value of a into equ2

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b = 40

the second number is 40.

I hope this helps.

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