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kkurt [141]
3 years ago
8

The number of incarcerated adults N​ (measured in​ thousands) in a certain country can be approximated by the equation Upper N e

quals negative 2.7 x squared plus 72.4 x plus 1911​, where x is the number of years since 2000. In 2013​, the number of incarcerated adults peaked. How many adults were incarcerated in that​ year?
Mathematics
2 answers:
xeze [42]3 years ago
8 0

Answer:

3308.5 thousands or 3,308,500.

Step-by-step explanation:

We have been given a formula that represented the number of incarcerated adults N​ (measured in​ thousands) in a certain country can be approximated by the equation N=2.7x^2+72.4x+1911 where x is the number of years since 2000.

To find the number of incarcerated adults in 2013, we will substitute x=13 (2013-2000=13) in the given equation.

N=2.7(13)^2+72.4(13)+1911

N=2.7*169+941.2+1911

N=456.3+941.2+1911

N=3308.5

Since the number of incarcerated adults N​ is measured in​ thousands, so the value of N would be:

3308.5\text{ thousands}=3308.5\times 1,000

3308.5\text{ thousands}=3,308,500

Therefore, 3,308,500 adults were incarcerated in 2013.

Pavlova-9 [17]3 years ago
4 0

Answer:

2,396,000 adults were incarcerated in 2013.

Step-by-step explanation:

The number of incarcerated adults N​ (measured in​ thousands) in a certain country can be approximated by the equation

N = -2.7x² + 72.4x + 1911

where x is the number of years since 2000.

In 2013, x = 2013 - 2000 = 13, and the number of incarcerated adults was

N = -2.7(13)² + 72.4(13) + 1911

N = -456.3 + 941.2 + 1911

N = 2,396

2,396 thousands (2,396,000) adults were incarcerated in 2013.

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