Ask question

Ask question

All categories

3 years ago

5

Simplify the - 501/2+12.3

1 answer:

SOVA2 [1]3 years ago

4 0

Answer:

$- 50 \frac{1}{2} + 12.3 \\ \\ = \frac{ - 101}{2} + 12.3 \\ \\ = - 38.2 \\ \\ = - 38 \frac{1}{5}$

You might be interested in

(10x^2+3x+9)+(5x^2+x+4) (10x 2 +3x+9)+(5x 2 +x+4)

BARSIC [14]

Answer:

50x^4 +25x^3 +103x^2 +25x +49

4 0

3 years ago

1. As part of a survey, 50 students were asked about their favorite lunch item. The results are shown in the table below .The ca

Fiesta28 [93]

1.
A. This statement is wrong because the prediction is valid, not valid.
B. Refer to A.
C.This statement is valid, yet explains the prediction incorrectly.
[D.] This statement is correct because 50 x 6 = 300, therefore 20% of 300 is 60.

2.

A. This is incorrect because it equals 125%
B. This is also incorrect, it equals 12.5%
C. Refer to B
[D.] This is correct, it equals 1.14%, which is less than 1.25%

7 0

3 years ago

If a =5, 0, −1,find a vector b such that compab = 2.b = _______.

Arturiano [62]

Answer:

$b = (q,r , 5q-2\sqrt{26} )$

Step-by-step explanation:

From the question we are told that

The vector given is

$a = (5,0,-1)$

Also $comp_a b = 2$

Generally

$comp_a b = \frac{a \cdot b}{|a|}$

Here $|a|$ is the magnitude of a which is mathematically represented as

$|a| = \sqrt{5^2 + 0^2 +(-1)^2 }$

=> $|a| = \sqrt{26}$

b is vector which we will assume to have the following parameters

$b = (q , r , x)$

So

$comp_a b = \frac{(5,0,-1) \cdot (q,r,x)}{\sqrt{26} } = 2$

=> $\frac{5q + 0 -x}{\sqrt{26} } = 2$

=> $x = 5q-2\sqrt{26}$

Hence the vector be can be mathematically represented as

$b = (q,r , 5q-2\sqrt{26} )$

This means that the vector b is more than one value since it is made up of variable

This means that if

$q = 1\\r=1\\x =1$

Then

$b = (1,1,5-2\sqrt{26} )$

7 0

3 years ago

PLEASE HELP ME FIGURE OUT THE REST OF THE TABLE FOR BRAINLIEST

sladkih [1.3K]

Answer:

Crimson: 2.5

Desert: 34.986

Emerald: 2.5

Fuschia: 10.66

4 0

3 years ago

Read 2 more answers

Aleksandr-060686 [28]

Answer:

$-\dfrac{463}{7}$

Explanation:

Given equation: 2x² - 6x - 7 = 0

In quadratic equation: ax² + bx + c

$Sum \ of \ roots : \alpha + \beta = \dfrac{-b}{a}$

$product \ of \ roots : \alpha \beta = \dfrac{c}{a}$

So, here given:

$Sum : \alpha + \beta = \dfrac{-(-6)}{2} = 3$

$Product : \alpha \beta = \dfrac{-7}{2} = - 3.5$

For finding value:

$\dfrac{\alpha^3}{\beta } + \dfrac{\beta^3 }{\alpha }$

join fractions

$\dfrac{\alpha^4+ \beta^4}{\alpha \beta }$

factor out

$\dfrac{(\alpha^2 + \beta ^2)^2 -2\alpha ^2 \beta ^2 }{\alpha \beta }$

when factored more

$\dfrac{((\alpha + \beta)^2 -2\alpha \beta )^2 -2(\alpha \beta)^2 }{\alpha \beta }$

insert values inside

$\dfrac{((3)^2 -2(-3.5) )^2 -2(-3.5)^2 }{-3.5 }$

calculate for value

$-\dfrac{463}{7}$

4 0

2 years ago