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Colt1911 [192]
3 years ago
5

Solvex +6> 10,x + 16>20,x + 26 > 30. Complete the description of a pattem. Then use the pattern to

Mathematics
1 answer:
Sergio [31]3 years ago
8 0

Answer:

x>4

x>4

x>4

Step-by-step explanation:

x+6>10

x+6-6>10-6

x>4

x+4,446>4,450

x+4,446-4,446>4,450-4,446

x>4

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the tile shown has a side length of 10.5 inches what power can you write to represent the area of the tile
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You could not do that then you would gey 110.25 which is what is not the question
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4 years ago
What is the solution of the equation e^xe^2x = 4? Round your answer to the nearest hundredth.
Stells [14]
The equation is:

[e^x] [e^(2x)] = 4

1) Applying property of multiplication of powers wiith same base =>

e ^ (x + 2x) = 4

=> e ^ (3x) = 4

2) Applying logarigth properties

3x = ln(4)

=> x = ln(4) / 3 ≈ 1.38629 / 3 ≈ 0.4621

Answer: x = ln(4) / 3 ≈ 0.4621
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4 years ago
Who sings, THE KID FRANKIE.
Arlecino [84]

Answer:

frankie

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Apples are sold in bags of four that cost $5, or bags of six that costs $7 per bag. What is the smallest cost at which you can b
babunello [35]
STEP 1:
BAGS OF FOUR
find number of bags needed to total 74 apples

= 74 ÷ 4 apples/bag
= 18.5 bags

*must round up to 19 bags because we cannot buy a partial bag

STEP 2:
BAGS OF FOUR
calculate price of 19 bags of 4 apples per bag

= 19 bags * $5/bag
= $95 for 19 bags of 4 apples/bag

STEP 3:
BAGS OF SIX
find number of bags needed to total 74 apples

= 74 ÷ 6 apples per bag
= 12.3333 bags needed

*must round up to 13 bags because we cannot buy a partial bag

STEP 4:
BAGS OF SIX

calculate price of 13 bags of 6 apples per bag

= 13 bags * $7 per bag
= $91 for 13 bags of 6 apples/bag


ANSWER: The smallest cost to buy 74 apples is $91.

Hope this helps! :)
3 0
3 years ago
Can you help me with number 6? <br> Confused abit <br> Please
Sunny_sXe [5.5K]

You can see the three diagram attached. Each link is labeled with the probability: you have probability 1/6 that a six is rolled, and 5/6 that it is not rolled.


To answer the questions, find the path that brings you to the desired outcome, and multiply all the labels you meet.


First question:

To get three sixes, you have to choose the left path at each roll. The probability is always 1/6, so the answer is


\frac{1}{6} \times \frac{1}{6} \times \frac{1}{6} = \frac{1}{6^3}


Second question:

To get no sixes, you have to choose the right path at each roll. The probability is always 5/6, so the answer is


\frac{5}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^3}{6^3}


Third question:

To get exactly one six, it can either be the first, second or third roll.


In all cases, you have to choose the left path once and the right path twice: left-right-right mean that you get the six in the first roll, right-left-right means that you get the six in the second roll, right-right-left means that you get the six in the third roll.


In every case, the left turn has probability 1/6, and the right turn has probability 5/6. The probability of each combination is thus


\frac{1}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^2}{6^3}


And since there are three of these combinations, The answer is


3\frac{5^2}{6^3}


Fourth question:

Since the question suggests to use what we already achieved, let's do it: having at least one six is the complementary event of having no sixes at all. If an event has probability p, its complementary has probability 1-p. So, since the probability of no sixes is known, the probability of at least one six is


1 - \frac{5^3}{6^3}

4 0
3 years ago
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