$\text{The area shaded outside of the triangle is}\\ \\ A=\frac{\pi r^2\theta}{360},\ r=5,\ \theta =80^o\\ \\ A=\frac{50\pi}{9}\\ \\ \text{Then we must add the area of the shaded triangle.}\\ \\ A=\frac{bh}{2}\\ \\ \frac{b}{2}=5sin40^o\\ \\ h=5cos40^o\\ \\ A=25sin40^o(cos40^o)\\ \\ \text{Total area is}\\ \\ A=\frac{50\pi }{9}+25sin40^o(cos40^o)\\ \\ A\approx 29.8cm^2$

8 0

3 years ago

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1. AC=EC 2.BC=DC 3.AB=DE

prisoha [69]

Answer:

1. AC = EC

Step-by-step explanation:

As it says that the figure has to be proved by SAS postulate. We know that, SAS stands for Side - Angle - Side, so we need to prove that any two sides and one angle of two triangles are equal/proportional or not.

Given, BC = CD, and angle ACB = angle DCE.

Therefore, the answer is 1. AC = EC.

8 0

3 years ago

What are the next two terms in the sequence? 2, 14, 26, 38, ...

ki77a [65]

Answer:

50, 62

The drawing will help

5 0

3 years ago

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