Question

A woman is 10 times as old as her daughter. In 8 years she will be 4 times as old as her daughter. How old is the mother now?

Answer 1

Answer:

80 years

Step-by-step explanation:

Let daughter's age be x years.

Therefore, women's age = 10x years

8 years after:

Daughter's age = (x + 8) years

Women's age = 4(x + 8) years

$4(x + 8) = (x + 8) \\ 4x + 32 = x + 8 \\ 4x - x8 - 32 \\ 3x = - 24 \\ x = \frac{ - 24}{3} \\ x = - 8 \\ \because \: age \: of \: a \: person \: can \: not \: be \: negative \\ \therefore \: x = 8 \\ \therefore \: 10x = 10 \times 8 \\ \huge \red{ \boxed{\therefore \: 10x = 80 \: years}}$

Answer 2

Answer:

Mom is 40 and her daughter is 4; in eight years, mom will be 48 and her daughter will be 12.

Step-by-step explanation: