Answer:
The correct code for this question:
g=float(input("Enter your English test grade:")) #take input from user.
#check conditions
if (g>=100 and g<=90):
print ("A")
#g greater then equal to 100 and less then equal to 90.
if (g>=89 and g<=80):
print("B")
#g greater then equal to 89 and less then equal to 80.
if (g>=79 and g<=70):
print("C")
#g greater then equal to 79 and less then equal to 70.
if (g>=69 and g<=65):
print("D")
#g greater then equal to 69 and less then equal to 69.
if(g<=64):
print("F")
#g less then equal to 64.
else:
print ("Not a grade")
#not a grade or fail.
Explanation:
In this program, we use to take a value from the user and check the value from the various conditions. To check all the condition we use if-else statement and AND operator that check to the range to together.
If -else is a conditional operator. In that, If block is used to check the true part and else part takes false value, and AND is a logical operator that check the two range together
Answer:
Answer is
By topic, By collection.
Refer below.
Explanation:
Quick SearchLinks to an external site. lets you refine or narrow your search results using links on the right side of the screen. Do a search on wind power. Some criteria that can refine your search results in Quick Search are:
By topic
By collection
Your answer would be a type
Answer:
The correct answer to the following question will be "Θ(n2)
". The further explanation is given below.
Explanation:
If we're to show all the objects that exist from either the first as well as the second vector, though not all of them, so we'll have to cycle around the first vector, so we'll have to match all the objects with the second one.
So,
This one takes:
=
And then the same manner compared again first with the second one, this takes.
=
Therefore the total complexity,
= Θ(n2)
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