Answer: Hello your question lacks some details attached below is the missing detail
answer :
a) True , B) False C) True D) True
Explanation:
a) True ; The critical section cannot be executed by more than one process at a time
b) False : The code does not satisfy the progress condition, because while loops are same hence no progress
c ) True : The code satisfies the bounded waiting condition, because of the waiting condition of the while loop
d) True : No matter how many times this program is run, it will always produce the same output, this is because of the while loop condition
true
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Answer:
import java.util.Arrays;
import java.util.Scanner;
public class LatinHire {
public static void main(String[] args) {
Scanner in = new Scanner (System.in);
System.out.println("Enter Five integers");
int num1 = in.nextInt();
int num2 = in.nextInt();
int num3 = in.nextInt();
int num4 = in.nextInt();
int num5 = in.nextInt();
int [] intArray = {num1,num2,num3,num4,num5};
System.out.println(Arrays.toString(intArray));
System.out.println("The Maximum is "+returnMax(intArray));
System.out.println("The Minimum is "+returnMin(intArray));
}
public static int returnMax(int []array){
int max = array[0];
for(int i=0; i<array.length; i++){
if(max<array[i]){
max= array[i];
}
}
return max;
}
public static int returnMin(int []array){
int min = array[0];
for(int i=0; i<array.length; i++){
if(min>array[i]){
min= array[i];
}
}
return min;
}
}
Explanation:
- This is implemented in Java Programming Language
- Two Methods are created returnMax(Returns the Maximum Value of the five numbers) and returnMin(Returns the minimum of the five numbers)
- In the Main method, the user is prompted to enter five numbers
- The five numbers are saved into an array of integers
- The returnMax and returnMin methods are called and passed the array as parameter.
- The entire array of numbers inputted by the user as well the Max and Min are printed
