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Aloiza [94]
3 years ago
6

At a butcher store, 5 1/2 pounds of hamburger meat are divided into 11 equal packages. How many pounds of meat will each package

contain?
Mathematics
2 answers:
Ede4ka [16]3 years ago
7 0

Each package will contain \frac{1}{2} pounds of meat in a butcher store.

<u>Solution:</u>

Given that total quantity of meat at butcher store = 5\frac{1}{2} pound

Number of package in which meat is equally divided = 11  

We need to determine meat in 1 package

As meat in 11 packages = 5\frac{1}{2} pound

Converting the mixed fraction we get,

5\frac{1}{2} = \frac{5 \times 2 + 1}{2} = \frac{11}{2}

=> Meat in 11 packages = \frac{11}{2} pounds

So meat in one package =\frac{11}{2} \div 11=\frac{1}{2}

Hence each package will contain \frac{1}{2} pounds

Alex787 [66]3 years ago
6 0

Answer:

each pack is 1/2 pound

Step-by-step explanation:

5.5 is 1/2 of 11

5.5/11=1/2

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zhenek [66]
Answer: (A - B)' = {1, 2, 3, 5, 6, 7, 8, 9, 10,12, 13}

Explanation:

The roster form of a set is the elements listed inside brackets { }.

In this case it is easy to visualize A - B directly of the Venn diagram: when you subtract from A those elements that are also in B, the result is A - B = {4, 11, 14}.

Now take into account tha (A - B)' is the complement of (A - B), this is all the elements that are not in A - B.

Being A - B = {4, 11, 14} then to show (A - B)' you just have to list all the elements that are on the figure except 4, 11 and 14.

The result, in roster form, is (A - B)' = {1, 2, 3, 5, 6, 7, 8, 9, 10, 12, 13}
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3 years ago
The cost of a bag of 8 peaches is $16. You could also buy individual peaches for
Veronika [31]

Answer: The peaches sold in bags

Step-by-step explanation:

16/8=2 This means that a single peach in the bag of peaches is worth $2. This is $0.15 cheaper than buying a single peach

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The unit rate for a single peach in the bag of peaches is $2

5 0
3 years ago
Determine the singular points of the given differential equation. Classify each singular point as regular or irregular. (Enter y
ludmilkaskok [199]

Answer:

Step-by-step explanation:

Given that:

The differential equation; (x^2-4)^2y'' + (x + 2)y' + 7y = 0

The above equation can be better expressed as:

y'' + \dfrac{(x+2)}{(x^2-4)^2} \ y'+ \dfrac{7}{(x^2- 4)^2} \ y=0

The pattern of the normalized differential equation can be represented as:

y'' + p(x)y' + q(x) y = 0

This implies that:

p(x) = \dfrac{(x+2)}{(x^2-4)^2} \

p(x) = \dfrac{(x+2)}{(x+2)^2 (x-2)^2} \

p(x) = \dfrac{1}{(x+2)(x-2)^2}

Also;

q(x) = \dfrac{7}{(x^2-4)^2}

q(x) = \dfrac{7}{(x+2)^2(x-2)^2}

From p(x) and q(x); we will realize that the zeroes of (x+2)(x-2)² = ±2

When x = - 2

\lim \limits_{x \to-2} (x+ 2) p(x) =  \lim \limits_{x \to2} (x+ 2) \dfrac{1}{(x+2)(x-2)^2}

\implies  \lim \limits_{x \to2}  \dfrac{1}{(x-2)^2}

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\implies  \lim \limits_{x \to2}  \dfrac{7}{(x-2)^2}

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Hence, one (1) of them is non-analytical at x = 2.

Thus, x = 2 is an irregular singular point.

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3 years ago
Is the following relation a function?
irina1246 [14]
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4 0
2 years ago
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solong [7]

Answer:

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Step-by-step explanation:

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4 0
4 years ago
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