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Marina86 [1]
3 years ago
7

Algebraic equations

Mathematics
2 answers:
anzhelika [568]3 years ago
7 0

1) 2x + 9  = 2x -5

            9 ≠ -5 ; No solution

2) 2x-  1 = x + 3

   x = 4; One solution x = 4

3) x + 2 = x + 2

   0 = 0; Identity (or all real numbers)

natali 33 [55]3 years ago
7 0

Answer:

1)  No solution

2) One solution x = 4

3) All real numbers

Hope this helps :)

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grandymaker [24]

Answer:

f(x)=-4(x-2)(x+7)

Or, in standard form:

f(x)=-4x^2-20x+56

Step-by-step explanation:

We can use the factored form of a quadratic equation:

f(x)=a(x-p)(x-q)

Where a is the leading coefficient and p and q are the zeros of the quadratic.

We know that the x-intercepts are at (2, 0) and (-7, 0).

So, let's substitute 2 for p and -7 for q. This yields:

f(x)=a(x-2)(x+7)

Now, we need to determine a.

We know that it passes through the point (1, 32). In other words, if we substitute 1 for x, we should get 32 for f(x). Therefore:

32=a(1-2)(1+7)

We can now solve for a. First, compute:

32=a(-1)(8)

Multiply:

32=-8a

Divide both sides by -8:

a=-4

So, the value of a is -4.

Therefore, our entire equation is:

f(x)=-4(x-2)(x+7)

Notes:

We can expand this into standard form:

f(x)=-4(x-2)(x+7) \\ f(x)=-4(x^2+5x-14) \\ f(x)=-4x^2-20x+56

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3 years ago
How are integers and their opposites related? give an example with numbers.
alukav5142 [94]

Answer:

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Answer:

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