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4 years ago

500 jelly beans are in a jar. 20% are red, 2/5 are orange. How many jelly beans are neither red or orange?

Mathematics

1 answer:

neonofarm [45]4 years ago

5 0

Answer:

200 jelly beans

Step-by-step explanation:

2/5 of 500= 200

20% of 500= 100

100+200=300

500-300=200

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At the beginning of the summer, Jenna had saved $141. To earn money over the summer, she is working part time at the local commu

Pepsi [2]

Answer:

y=24x+141

Step-by-step explanation:

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4 years ago

An earthquake was felt throughout a circular area of 1808.64 Square miles what was the radius of the circular area

lozanna [386]

Answer:

Step-by-step explanation:

The area of a circle is given by the formula:

$A=\pi r^2$

Where <em>A</em> is the area and <em>r</em> is the radius.

Since we already know the area, we can plug it in and solve for <em>r</em>. Thus:

$1808.64=\pi r^2\\$

Divide both sides by π. We can use 3.14 as an approximation. The πs on the right cancel out:

$1808.64\div(3.14)=r^2\\r^2=576$

Take the square root of each side:

$\sqrt{r^2}=\sqrt{576}$

The squares on the left cancel. The root of 576 is 24:

$r=24$

Therefore, the radius is 24.

3 0

3 years ago

If you are pocking a number between 1-20 what is the probability that you will pick a number greater than 14 or less than 4?

iVinArrow [24]

9/20.... Also is the worksheet you’re working on?

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3 years ago

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Elan Coil [88]

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3 years ago

The circumference of a sphere was measured to be 82 cm with a possible error of 0.5 cm. (a) Use differentials to estimate the ma

NeTakaya

Answer:

The Maximum error is $26cm^2$

Step-by-step explanation:

Given that the circumference of a sphere was measured to be 82 cm with a possible error of 0.5 cm

<h3>To find :</h3><h3>(a) Use differentials to estimate the maximum error in the calculated surface area. (Round your answer to the nearest integer.) $cm^2$ </h3>

Given circumference of a sphere=82 cm and possible error =0.5 cm

Error of the surface area is dA

Error of circumference is dC = 0.5 cm

We know that the formula for Circumference of a sphere is C=2πr units

Differentiating with respect to r

$dC = 2\pi dr$

$dr =\frac{dC}{2π}$

$=\frac{0.5}{2\pi}$ (∵ dC = 0.5 cm)

<h3>Since Area $A = 4\pi r^2$ square units</h3>

Differentiating with respect to r

$dA = 8\pi rdr$ square units

Since given C = 82 cm.and also C=2πr we have

$r=\frac{C}{2π}$

$=\frac{82}{2π}$

$r=\frac{41}{π}$

From that $dA = 8\pi rdr$

Substituting the values of r and dr in the above equation we get

$dA = 8\pi (\frac{41}{\pi}) (\frac{0.5}{2\pi})$

$=4(41)\times (\frac{0.5}{3.14})$

$=26.1146$

$dA=26cm^2$

∴ Maximum error is $26cm^2$

4 0

4 years ago