The limit of sqrt(9x^4 + 1)/(x^2 - 3x + 5) as x approaches infinity is
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Answer:
C. 11
Step-by-step explanation:
First, find the value of "x" by solving the first equation. You need to move every other number to the other side of "x". When you move a number, you have to do the opposite operation to both sides.
5x + 6 = 10 The opposite of +6 is -6.
5x + 6 - 6 = 10 - 6 Subtract 6 from both sides
5x = 10 - 6 The "6" on the left cancelled out. Simplify the right side
5x = 4 The opposite of multiply by 5 is divide by 5
5x/5 = 4/5 Divide both sides by 5
x = 4/5 Value of "x"
Substitute the value of "x", which is 4/5, in the "x" for the second equation.
10x + 3
= 10(4/5) + 3 Multiply 10 and 4/5
= + 3 Combine into the numerator
= + 3 Divide the top by the bottom
= 8 + 3 Add
= 11 Value of second equation
Therefore the value of 10x + 3 is 11.