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Pani-rosa [81]
2 years ago
8

Yahto needs 3 3/4 cups of sugar to make cookies. He needs an additional 3/4 cup for bread. Find the total amount.

Mathematics
1 answer:
r-ruslan [8.4K]2 years ago
6 0

Answer:

 your answer would be 4.5

Step-by-step explanation:

because if you take the 3/4 from 3 and turn it into a decimal it would be 0.75 so 0.75 + 0.75 is 1.5 and 3 + 1.5 = 4.5

i hope i helped you

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I need answer please​
weqwewe [10]

Answer:

y = -3/2x + 6

Step-by-step explanation:

Parallel lines have the same slope so slope is -3/2

Using (4,0)

y = mx + b

0 = -3/2(4) + b

0 = -6 + b

b = 6

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4 0
2 years ago
Which answer has the smallest value?
Mademuasel [1]

Answer:

The smallest value is 2) the opposite of 50 because it is farthest left of the zero (this makes it the smallest)

Step-by-step explanation:

1) = 100

2) = -50

3) = 0

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3 years ago
Read 2 more answers
Solve the right triangle <br>round your answer to the nearest tenth.​
ICE Princess25 [194]

Answer:

Use SOH-CAH-TOA method and figure out which sign you need. SOH- Sin, CAH- Cos, TOA- Tan.

Also,

SOH- opposite/hypotenuse

CAH- adjacent/hypotenuse

TOA- opposite/adjacent

Look at the angle and see which terms you have already. For example, if you had opposite the angle and the adjacent side, you would choose tangent because its TOA. Hope that helps!

6 0
3 years ago
How is the product of 4 and 2 shown using integer tiles?
Alex
+ + + + + +
4 is positive or + and so is 2
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8 0
3 years ago
each time kim pour water from a jug into a glass, exactly 10% of the water remaining in the jug is used. What is the minimum num
Gnoma [55]

The <em><u>correct answer</u></em> is:

At least 7 times.

Explanation:

Since 10% of the water in the jug is removed each time, this means that 100-10=90% of the water remains.

After two times, we would have 0.9(0.9) = 0.81 = 81% of the water; each time she pours, the number of times 0.9 is multiplied by itself changes.  This makes this an exponential inequality (it is not an equation, as we want "less than half of the water"):

0.5 < 0.9^x

To solve this, we will use logarithms:

\log_{0.9}(0.5)

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3 years ago
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