x+x+y.y.y = 2x+y^3 ( y cube)
So, The answer is (d)
First we rewrite the functions:
y = 2x
y = x ^ 10
We note that the second function always has values of y greater than the first function. However, there is a value of x for which the first function is greater.
For x = 1 we have:
y = 2 (1) = 2
y = (1) ^ 10 = 1
We note that:
2> 1
Answer:
Yes, the value of function y = 2x eventually exceed the value of function y = x ^ 10.
Answer:
Step-by-step explanation:
y=3x+3, y=6x-6
6x-6=3x+3
3x=9
x=3
Around 70-80 depending on how many people I’m texting
Answer:
4534443242
Step-by-step explanation:
