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2 years ago

6

Hector works 12 hours per week at a part-time

1 answer:

rewona [7]2 years ago

6 0

Answer:

Step-by-step explanation:

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Answer:

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2 years ago

How can I get help with linear equations with fractions? I dont remember how to solve

xz_007 [3.2K]

Answer:

to find the missing number, compare both sides of the equation. If the variable terms are the same and the constant terms are different, then the equation has no solutions.

Step-by-step explanation:

to find the missing number, compare both sides of the equation. If the variable terms are the same and the constant terms are different, then the equation has no solutions.

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2 years ago

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3 years ago

What is this math problem? -15a=17

Anestetic [448]

Answer:

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Step-by-step explanation:

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3 years ago

Circles are described below by the coordinates of their centers, C, and one point on their circumference, A. Determine an equati

Art [367]

Using the given center and point at the circumference, the equation of the circles are:

a) $(x - 5)^2 + (y - 2)^2 = 100$

b) $(x + 2)^2 + (y + 5)^2 = 169$

c) $(x - 5)^2 + (y + 1)^2 = 65$

<h3>What is the equation of a circle?</h3>

The equation of a circle of radius r and center $(x_0,y_0)$ is given by:

$(x - x_0)^2 + (y - y_0)^2 = r^2$

Item a:

Center C(5,2), hence $x_0 = 5, y_0 = 2$ .

The point at the circumference is A(11,10), hence:

$(x - 5)^2 + (y - 2)^2 = r^2$

$(11 - 5)^2 + (10 - 2)^2 = r^2$

$r^2 = 100$

Hence:

$(x - 5)^2 + (y - 2)^2 = 100$

Item b:

Center C(-2,-5), hence $x_0 = -2, y_0 = -5$ .

The point at the circumference is A(3,-17), hence:

$(x + 2)^2 + (y + 5)^2 = r^2$

$(3 + 2)^2 + (-17 - 5)^2 = r^2$

$r^2 = 169$

Hence:

$(x + 2)^2 + (y + 5)^2 = 169$

Item c:

Center C(5,-1), hence $x_0 = 5, y_0 = -1$ .

The point at the circumference is A(-2,-5), hence:

$(x - 5)^2 + (y + 1)^2 = r^2$

$(-2 - 5)^2 + (-5 + 1)^2 = r^2$

$r^2 = 65$

Hence:

$(x - 5)^2 + (y + 1)^2 = 65$

You can learn more about equation of a circle at brainly.com/question/24307696

4 0

2 years ago