The mean of children in 5 families is 3. How many children might be in each family if none of them have 3 children??
1 answer:
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Answer:
z = -2.85
Step-by-step explanation:
Since the number of nuts per can is normally distributed:
Mean number of nuts (μ)= 500 nuts
Standard Deviation (σ)= 20 nuts
X = 443 nuts
For any given number of nuts X, the z-score is given by:
The z-score for this can of nuts with 443 nuts is -2.85.