All categories

3 years ago

3. Sylvia wants to go on a cruise around the world in 5 years. If she puts $50 into an

Mathematics

1 answer:

Veseljchak [2.6K]3 years ago

3 0

Answer:

$13,756.31

Step-by-step explanation:

The computation of the amount at the end of the five years is shown below:

Here we applied the FV formula

Given that

NPER = 5 × 52 = 260

RATE = 2.25% ÷ 52 = 0.043269%

PV = $0

PMT = $50

The formula is given below:

=-FV(RATE;NPER;PMT;PV;TYPE)

After applying the above formula, the future value is $13,756.31

You might be interested in

Both circle Q and circle R have a central angle measuring 75°. The ratio of circle Q's radius to circle R's radius is 2:5. Which

ycow [4]

The ratio of similar areas is the square of the ratio of the scale factor.

Circle R's sector is (5/2)² = 25/4 the area of Circle Q's sector.

7 0

3 years ago

Read 2 more answers

If you are traveling 543 miles and you know that your car gets 18 miles per gallon of gasoline, approximately how many gallons o

Inga [223]

we know that

the car gets 18 miles per -----------> 1 gallon of gasoline

for 543 miles ---------------------> x gallons of gasoline

by proportion

543/18=x/1---------->x=543/18------->x=30.17 gallons

therefore

the answer is

30.17 gallons

6 0

3 years ago

Is the sequence geometric if so identify the common ratio 1/3, 2/9, 4/27, 8/81, 16/243

docker41 [41]

Yes it is a geometric sequence and the common ratio is 2/3

3 0

3 years ago

Read 2 more answers

How do you use the order of operations to evaluate expressions with exponents?

IgorLugansk [536]

Using BEDMAS, it would be brackets first, so anything Inside a set of brackets would be solved first, and would follow the same rule. Once the brackets have been solved, next would be the exponents. Since your brackets have been solved you can expand with the exponents. After exponents, would be anything that has to be divided or multiplied. These two operations are interchangeable based on what is more convenient or beneficial to do first. And lastly, addition and subtraction, which once again are interchangeable operations

5 0

3 years ago

What is the exact area and arc length of these sectors? Please helppp

Karolina [17]

<u>Answers with step-by-step explanation:</u>

1. Area of sector 1 = $\frac{90}{360} \times \pi \times 12^2 = 36\pi$

2. Area of sector 2 = $\frac{45}{360} \times \pi \times 19^2 = \frac{2527}{8} \pi$

3. Area of sector 3 = $\frac{270}{360} \times \pi \times 15^2 = \frac{675}{4} \pi$

4. Area of sector 4 = $\frac{270}{360} \times \pi \times 6^2 = 27 \pi$

5. Arc length of sector 1 = $\frac{90}{360} \times 2 \times \pi \times 12 = 6\pi$

6. Arc length of sector 2 = $\frac{315}{360} \times 2 \times \pi \times 19 = \frac{133}{4} \pi$

7. Arc length of sector 3 = $\frac{270}{360} \times 2 \times \pi \times 15 = \frac{45}{2}\pi$

8. Arc length of sector 4 = $\frac{270}{360} \times 2 \times \pi \times 6 = 9\pi$

4 0

3 years ago