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3 years ago

Mary has 36

Mathematics

1 answer:

morpeh [17]3 years ago

3 0

Answer: i dont know if this is correct but i think the answer is.... tom will have 74 apples

Step-by-step explanation:

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What are the x-intercepts of the graph of y= x^2 + 7x + 12?

jok3333 [9.3K]

Answer:

B. (-4,0) and (-3,0)

Step-by-step explanation:

I used a graphing tool to graph the equation. The parabola intercepts at (-4,0) and (-3,0). Therefore, (-4,0) and (-3,0) are the x-intercepts of the equation.

Option B should be the correct answer.

5 0

4 years ago

Find the sum. (13x2 + 5x) + 8x2 =

Julli [10]

The sum is the total of the given values being added.
Given the expressions above, to add them, you just have to add the numbers with the same terms. 13x2 and 8x2 have the same terms which is x2, therefore, you can add both and the result is 21x^2 then just copy 5x so the sum would be 21x2 + 5x. Hope this answer helps.

4 0

3 years ago

HELP DUE SOON 20 POINTS

Mariulka [41]

Answer:

x = 10

Step-by-step explanation:

m∠KNL = 90

10x - 10 = 90

10x = 100

x = 10

5 0

3 years ago

Draw and label a picture to show how knowing 7+7 helps you find 7+8

madreJ [45]

Lets say we have 7 items, and we add 7 more.
Then, in the next situation, we have 7 items and we add 8 more. Now we know that 8 = 7 + 1, so we are actually performing 7 + 7 +1. Our diagram already shows us the value of 7 + 7 so we just add 1.
The items can be represented by circles, triangles etc

3 0

4 years ago

Question -

Sauron [17]

$\rule{200}4$

Answer : The required ratio is (14m-6):(8m+23) .

$\rule{200}4$

Here we are given that the ratio of sum of first n terms of two AP's is (7n + 1):(4n + 27) .

That is.

$\small\sf\longrightarrow \dfrac{S_1}{S_2}=\dfrac{7n +1}{4n +27} \\$

As , we know that the sum of n terms of an AP is given by ,

$\small\sf\longrightarrow \pink{ S_n =\dfrac{n}{2}[2a +(n-1)d]} \\$

Assume that ,

First term of 1st AP = a
First term of 2nd AP = a'
Common difference of 1st AP = d
Common difference of 2nd AP = d'

Using this we have ,

$\small\sf\longrightarrow \dfrac{S_1}{S_2}=\dfrac{\dfrac{n}{2}[2a + (n-1)d]}{\dfrac{n}{2}[2a' +(n-1)d'] } \\$

$\small\sf\longrightarrow \dfrac{7n+1}{4n+27}=\dfrac{2a + (n -1)d}{2a' + (n -1)d' } . . . . . (i) \\$

Now also we know that the nth term of an AP is given by ,

$\longrightarrow\sf\small \pink{ T_n = a + (n-1)d}\\$

Therefore,

$\longrightarrow\sf\small \dfrac{T_{m_1}}{T_{m_2}}= \dfrac{ a + (n-1)d }{a'+(n-1)d'}. . . . . (ii)\\$

$\longrightarrow\sf\small \dfrac{T_1}{T_2}=\dfrac{2a + (2n-2)d}{2a'+(2n-2)d'} . . . . . (iii)\\$

From equation (i) and (iii) ,

$\longrightarrow\sf\small n-1 = 2m-2\\$

$\longrightarrow\sf\small n = 2m -2+1 \\$

$\longrightarrow\sf\small n = 2m -1 \\$

Substitute this value in equation (i) ,

$\longrightarrow \sf\small \dfrac{2a+ (2m-1-1)d}{2a' +(2m-1-1)d'}=\dfrac{7(2m-1)+1}{4(2m-1) +27}\\$

Simplify,

$\longrightarrow\sf\small \dfrac{ 2a + (2m-2)d}{2a' +(2m-2)d'}=\dfrac{14m-7+1}{8m-4+27}\\$

$\longrightarrow\sf\small \dfrac{2[a + (m-1)d]}{2[a' + (m-1)d']}=\dfrac{ 14m-6}{8m+23}\\$

$\longrightarrow\sf\small \dfrac{[a + (m-1)d]}{[a' + (m-1)d']}=\dfrac{ 14m-6}{8m+23}\\$

From equation (ii) ,

$\longrightarrow\sf\small \underline{\underline{\blue{ \dfrac{T_{m_1}}{T_{m_2}}=\dfrac{ 14m-6}{8m+23}}}}\\$

$\rule{200}4$

8 0

3 years ago