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iren [92.7K]
3 years ago
14

Consider the expression.

Mathematics
1 answer:
Dmitrij [34]3 years ago
7 0

-1629.8

Step-by-step explanation:

pemdas first parenthesis,then exponents. then multiplication, division,the addition and finally subtraction

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PLEASE HELP!!!!!!!!!!!!! DUE SOON
Sergio039 [100]

\bf ~~~~~~\textit{initial velocity} \\\\ \begin{array}{llll} ~~~~~~\textit{in feet} \\\\ h(t) = -16t^2+v_ot+h_o \end{array} \quad \begin{cases} v_o=\stackrel{}{\textit{initial velocity of the object}}\\\\ h_o=\stackrel{}{\textit{initial height of the object}}\\\\ h=\stackrel{}{\textit{height of the object at "t" seconds}} \end{cases} \\\\[-0.35em] ~\dotfill\\\\ h=-16t^2+\stackrel{\stackrel{v_o}{\downarrow }}{65}t


now, take a look at the picture below, so for 2) and 3) is the vertex of this quadratic equation, 2) is the y-coordinate and 3) the x-coordinate.


\bf \textit{vertex of a vertical parabola, using coefficients} \\\\ h=\stackrel{\stackrel{a}{\downarrow }}{-16}t^2\stackrel{\stackrel{b}{\downarrow }}{+65}t\stackrel{\stackrel{c}{\downarrow }}{+0} \qquad \qquad \left(-\cfrac{ b}{2 a}~~~~ ,~~~~ c-\cfrac{ b^2}{4 a}\right) \\\\\\ \left( -\cfrac{65}{2(-16)}~~,~~0-\cfrac{65^2}{4(-16)} \right) \implies \left( \cfrac{65}{32}~,~0- \cfrac{4225}{-64}\right)


\bf \left( \cfrac{65}{32}~,~0+ \cfrac{4225}{64}\right)\implies \left( \stackrel{seconds}{2\frac{1}{32}}~~,~~ \stackrel{feet~hight}{66\frac{1}{64}}\right)

6 0
3 years ago
Solve for x: y=-3x+6
vazorg [7]
The answer is : x= -y/3+2
8 0
3 years ago
Read 2 more answers
All you need is on the photo
mariarad [96]

Answer:

4^{-3}

Step-by-step explanation:

We\ are\ given\ that,\\4^4*4^{-8}*4\\We\ know\ that,\ for\ any\ real\ number\ n, n^a*n^b=n^{(a+b)}\\Hence,\\First,\ lets\ write\ all\ the\ terms\ in\ an\ exponential\ form.\\4^4*4^{-8}*4^1\\=4^{(4+(-8)+1)}\\=4^{(5-8)}\\=4^{-3}

5 0
3 years ago
Help plz <br><br> 6yd - 2ft 7in
Arlecino [84]
185 in because because becuase i searches it up up yp up up up up up up
6 0
3 years ago
JUAN DECIDE PINTAR LAS PAREDES DE SU CASA UN TOTAL DE 200 METROS LOS DOS PRIMEROS DIAS PINTO 33 METROS CADA DIA AL TERCER DIA CO
Stells [14]

Answer:

38 metros

Step-by-step explanation:

Número total de metros que Juan quiere pintar su casa = 200 m

Durante los primeros 2 días, pintó = 33 m todos los días

Por lo tanto, el número total de metros que pintó = 33 m × 2 = 66 m

Al tercer día, practica la pintura = 96 m

El número de metros que quedan por pintar se calcula como:

200m - (66m + 96m)

Los 200m - 162m

= 38m

8 0
3 years ago
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