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3 years ago

Write 25 x 10in standard form.

Mathematics

1 answer:

Sonbull [250]3 years ago

6 0

Answer:

Step-by-step explanation:

25 x 10=250

standard form is 2.5 x 10²

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PLEASE HELP! ANY SPAM ANSWERS WILL BE REPORTED!

Rainbow [258]

Answer:

Rise: -1 Run: -1

Step-by-step explanation:

It's a negative line, and it crosses at the corner of every line. Hope this helps :)

7 0

2 years ago

Read 2 more answers

What is the length of a hypotenuse when the legs are 5 and 12

Alisiya [41]

By using pythagoras theorem where
(Base)^2 +(perpedicular)^2 = (hypotenuse)^2
So,
(5)^2 +(12)^2 = (hypotenuse)^2
25 + 144 = (hypotenuse)^2
169 = (hypotenuse)^2
13 = hypotenuse

So, hypotenuse = 13

8 0

3 years ago

The second term in a geometric series is 10, and the seventh term is 10,240. Find the sum of the first six terms.

just olya [345]

Answer:

The sum of the first 6 terms is 3,412.5.

Step-by-step explanation:

The second term of the geometric series is given by:

$a_{2}=a_{1}*r$

Where a1 is the first term and r is the common ratio. The seventh term can be written as a function of the second term as follows:

$a_{7}=a_{1}*r^{6} \\a_{7}=a_{2}*r^{5} \\10,240 = 10*r^{5}\\r=\sqrt[5]{1024} \\r = 4$

The sum of "n" terms of a geometric series is given by:

$a_{1} = \frac{10}{4} = 2.5\\S_{n}=a_{1}(\frac{r^{n}-1 }{r-1})\\S_{6}=2.5(\frac{4^{6}-1 }{4-1})\\S_{6}=3,412.5$

The sum of the first 6 terms is 3,412.5.

5 0

3 years ago

In 2015, the population of the United States was about 320 million people. About 7 out of 10 Americans live in urban areas. How

Kay [80]

224million is the correct answer.
7/10 of 320,000,000 is 224,000,000

7 0

2 years ago

The output of an economic system Q, subject to two inputs, such as labor L and capital K, is often modeled by the Cobb-Dougl

Anna35 [415]

Answer:

Step-by-step explanation:

Given

Economic system Q is given by

$Q=cL^aK^b$

also $a+b=1$

if $Q=12,200$

$a=\frac{1}{6}$

$b=\frac{5}{6}$

$c=42$

substitute these values

$12,200=42\times (L)^{\frac{1}{6}}K^{\frac{5}{6}}$

$(L)^{\frac{1}{6}}K^{\frac{5}{6}}=\frac{12,200}{42}$

$K^{\frac{5}{6}}=\frac{12,200}{42(L)^{\frac{1}{6}}}$

$K=(\frac{12,200}{42})^{\frac{6}{5}}\times \frac{1}{L^{5}}$

differentiate w.r.t to L to get $\frac{dK}{dL}$

$\frac{dK}{dL}=(\frac{12,200}{42})^{\frac{6}{5}}\times (-5)\times L^{-6}$

$\frac{dK}{dL}=-5(\frac{12,200}{42})^{\frac{6}{5}}\times \frac{1}{L^6}$

$\frac{dK}{dL}=-\frac{4515.466}{L^6}$

6 0

3 years ago