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german
3 years ago
12

A certain forest covers an area of 4500 km^2. Suppose that each year this area decreases by 8.75%. What will the area be after 5

years?
Mathematics
1 answer:
Virty [35]3 years ago
8 0

The area of forest after 5 years is 2846.93 square kilometer

<em><u>Solution:</u></em>

Given that, A certain forest covers an area of 4500 square kilometer

Suppose that each year this area decreases by 8.75%

To find: Area after 5 years

<em><u>The decrease function is given as:</u></em>

y = A(1-r)^t

Where,

y is the value after t years

A = initial amount

r = decreasing rate in decimal

t is the number of years

Here in this sum,

A = 4500

t = 5 years

r = 8.75 \% = \frac{8.75}{100} = 0.0875

<em><u>Substituting the values in formula, </u></em>

\begin{aligned}&y=4500(1-0.0875)^{5}\\\\&y=4500(0.9125)^{5}\\\\&y=4500 \times 0.632651\\\\&y=2846.93\end{aligned}

Thus the area of forest after 5 years is 2846.93 square kilometer

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Step 2: Divide the interval \left[0,\frac{3 \pi}{4}\right] into n = 6 sub-intervals of length \Delta{x}=\frac{\pi}{8}

a=\left[0, \frac{\pi}{8}\right], \left[\frac{\pi}{8}, \frac{\pi}{4}\right], \left[\frac{\pi}{4}, \frac{3 \pi}{8}\right], \left[\frac{3 \pi}{8}, \frac{\pi}{2}\right], \left[\frac{\pi}{2}, \frac{5 \pi}{8}\right], \left[\frac{5 \pi}{8}, \frac{3 \pi}{4}\right]=b

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f\left(x_{1}\right)=f\left(\frac{\pi}{8}\right)=3 \sqrt{\frac{\sqrt{2}}{4} + \frac{1}{2}}=2.77163859753386

f\left(x_{2}\right)=f\left(\frac{\pi}{4}\right)=\frac{3 \sqrt{2}}{2}=2.12132034355964

f\left(x_{3}\right)=f\left(\frac{3 \pi}{8}\right)=3 \sqrt{\frac{1}{2} - \frac{\sqrt{2}}{4}}=1.14805029709527

f\left(x_{4}\right)=f\left(\frac{\pi}{2}\right)=0=0

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