Solving a system of equations we will see that we need to use <u>40 liters of the 80% acid solution</u>, and the other <u>20 liters are of the 35% acid solution</u>.
<h3>
How many liters of each solution do we need to use?</h3>
First, we need to define the variables:
- x = liters of the 35% acid used.
- y = liters of the 80% acid used.
We know that we want to produce 60 liters of 65% acid, then we have the system of equations:
x + y = 60
x*0.35 + y*0.80 = 60*0.65
(in the second equation we wrote the percentages in decimal form).
To solve this we need to isolate one of the variables in one equation and then replace it in other one, isolating x we get:
x = 60 - y
Replacing that in the other equation:
(60 - y)*0.35 + y*0.80 = 60*0.65
y*(0.80 - 0.35) = 60*(0.65 - 0.35)
y*0.45 = 60*0.30
y = 60*0.30/0.45 = 40
So we need to use <u>40 liters of the 80% acid solution</u>, and the other <u>20 liters are of the 35% acid solution</u>.
If you want to learn more about systems of equations:
brainly.com/question/13729904
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Answer:
ASA
Step-by-step explanation:
In given triangle
Line BC = Line QR
Angle ABC = Angle PQR
Angle ACB = Angle PRQ
Computation:
Angle ABC = Angle PQR (Angle)
Line BC = Line QR (Side)
Angle ACB = Angle PRQ (Angle)
So,
ΔABC ≅ ΔPQR
By Angle Side Angle property
ASA
I’m so sorry! I hope you find the answer soon! I’m stressing out as well
Answer:
y = 3/4x + 7
Step-by-step explanation:
Put it in point-slope form:
y - 4 = 3/4(x - -4)
y - 4 = 3/4(x + 4)
y - 4 =3/4x + 3
y = 3/4x + 7
Answer:
7
Step-by-step explanation:
4- Ones
6- tenths
0-hundredths
3-thousandths
7-ten-thousandths
Hope this helps! :)
