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3 years ago

How many year apart is 384 BC from 1952 AD

2 answers:

6 0

BC and BCE are Before Common Era
So what you want to do is add 1952 and 384
1952 + 384 = 2336
So the amount of years between 384 BC and 1952 AD is about 2,336 years
Hope this helps

Ne4ueva [31]3 years ago

4 0

So you have to make a number line from 384 bc a negative numb r to 1952 ad this is a positive number for example -384+1952= then you have your answer

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Find the value of the 60th term of the following sequence: 33, 28, 23, 18

Otrada [13]

Step-by-step explanation:

The first term of the AP i.e a = 33

and common difference i.e d = 28-33 = -5

So, 60th term = a +(n-1)d = a+ 59d

= 33 + 59( -5)

= 33- 295

= - 262

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2 years ago

What is the slope and y-intercept of the line 3x - 4y = 12?*

Lorico [155]

Answer:

m = 3/4; b = -3

Step-by-step explanation:

1) First, put the given equation into slope-intercept form. This is so we can identify its slope and y-intercept easily. Isolate y:

$3x-4y = 12\\-4y = -3x+12\\y = \frac{3}{4} x-3$

2) Lines that are in slope-intercept form are represented by the formula $y = mx + b$ . The number in place of $m$ , or the coefficient of the x-term, represents the slope. The number in place of $b$ represents the y-intercept. So, the slope of $y = \frac{3}{4} x-3$ is $\frac{3}{4}$ , and its y-intercept is -3.

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3 years ago

A book store sells a textbook for $150. If the textbook is on sale with 12% off, and there is a sales tax of 8.25% added to the

Yuri [45]

The textbook is $150 originally, so to find the price of the textbook on sale, multiply the original price by 12% (0.12). Then subtract 12% of 150 from 150.

150 * 0.12 = 18

Subtract 18 from 150.

150 - 18 = 132

Multiply the price of the textbook on sale by the sales tax of 8.25% (0.0825). Then add the tax price onto the sale price of the textbook.

132 * 0.0825 = 10.89

Add 10.89 to 132.

132 + 10.89 = 142.89

The final price of the textbook is $142.89.

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3 years ago

HELPPP

lana [24]

Answer:

so what are we trying to figure out?

Step-by-step explanation:

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2 years ago

A businessman was comparing his company's profits for two consecutive months. In November, n, were 0.04 thousand dollars more th

Firdavs [7]

N and d are both numbers of thousands of dollars.
Thus, if n = 1, that means $1000.

Here n = d + 0.4.
Note that in C, n+0.04=n is completely wrong.
Similarly, in D, d = 0.04 = n is completely wrong.
The "combined profit amount" for Nov. and Dec. is n + d = 3.15.

Only A matches this info. Your answer is A.

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3 years ago