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3 years ago

I don't understand how to do these probability questions, what two fractions do I multiply to get these answers?

Mathematics

1 answer:

Lunna [17]3 years ago

6 0

I believe the two fractions are the numbers they all have in common.

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I need help with this question asap

Nataly_w [17]

Answer:

The correct answer would be the bottom equation.

Step-by-step explanation:

y=7.25x

y=7.25(3)

y=21.75

y=7.25(4)

y=29.00

y=7.25(5)

y=36.25

7 0

3 years ago

Find the third side in simplest radical form:<br> 25

Gre4nikov [31]

Answer:

<h3> $\boxed{ \bold{24}}$ </h3>

Step-by-step explanation:

$\mathsf{given}$

$\mathsf{hypotenuse(h) = 25}$

$\sf{perpendicular (p) = 7}$

$\sf{base(b) = }$ ?

Now, Using Pythagoras theorem

$\sf{{h}^{2} = {p}^{2} + {b}^{2} }$

plug the values

⇒ $\sf{ {25}^{2} = {7}^{2} + {b}^{2} }$

Evaluate the power

⇒ $\sf{625 = 49 + {b}^{2} }$

Swap the sides of the equation

⇒ $\sf{49 + {b}^{2} = 625}$

Move constant to right hand side and change it's sign

⇒ $\sf{ {b}^{2} = 625 - 49}$

Calculate the difference

⇒ $\sf{ {b}^{2} = 576}$

Squaring on both sides

⇒ $\sf{b = 24}$

Hope I helped!

Best regards!

8 0

3 years ago

How would you do this question?

diamong [38]

Answer:

1) ∫ x² e^(x) dx

4) ∫ x cos(x) dx

Step-by-step explanation:

To solve this problem, eliminate the choices that can be solved by substitution.

In the second problem, we can say u = x², and du = 2x dx.

∫ x cos(x²) dx = ∫ ½ cos(u) du

In the third problem, we can say u = x², and du = 2x dx.

∫ x e^(x²) dx = ∫ ½ e^(u) du

8 0

3 years ago

An item is regularly priced at

jekas [21]

85% = 0.85

1-0.85 = 0.15

80 x 0.15 = 12

the price now is $12

7 0

3 years ago

The number in each column are related. The goal is to determine how they are related, determine which numbers belongs in the bla

andre [41]

Answer:

If you cube the numbers in the left column, you get the numbers in the right column! We can figure this out by understanding that 1^3 = 1, 3^3 = 27, and 6^3 = 216. Then it all falls into place!

1 -> 1

2 -> 8

3 -> 27

5 -> 125

6 -> 216

11 -> 1331

8 -> 512

10 -> 1000

7 -> 343

14 -> 2744

p -> $p^{2}$

$\sqrt{q}$ -> q

8 0

3 years ago

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