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lara31 [8.8K]
2 years ago
8

color%7Bred%7D%20Question%7D%7D%7D%7D" id="TexFormula1" title=" \huge{\green}\fcolorbox{blue}{cyan}{\bf{\underline{\red{\color{red} Question}}}}" alt=" \huge{\green}\fcolorbox{blue}{cyan}{\bf{\underline{\red{\color{red} Question}}}}" align="absmiddle" class="latex-formula">
\mathsf \blue{sketch \: the \: graph \: of}
\mathsf \blue{y \geqslant x + 1}
​
Mathematics
1 answer:
madreJ [45]2 years ago
8 0

Answer:

Graph attached →

Step-by-step explanation:

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3

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If the ordinate is three more than twice the abscissa and x E {-1,0,-1/3} which of the following sets of ordered pairs satisfies
almond37 [142]
<span>The ordinate is three more than twice the abscissa
</span>Ordnate: y; Abscissa: x
y=3+2x

x=-1→y=3+2(-1)=3-2→y=1→(x,y)=(-1,1)
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x=-1/3→y=3+2(-1/3)=3-2/3=(3*3-2)/3=(9-2)/3→y=7/3→(x,y)=(-1/3,7/3)

Answer: Option <span>A) {(-1,1),(0,3),(-1/3,7/3)}</span>
8 0
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NEED HELP ASAP 70 POINTS
Vera_Pavlovna [14]

Look at the picture.

We have the similar triangles (AAA). Therefore the lengths of the sides are in proportion:

\dfrac{x}{8}=\dfrac{15}{5}

\dfrac{x}{8}=3           <em>multiply both sides by 8</em>

\boxed{x=24\ in}

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3 years ago
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