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lara31 [8.8K]
2 years ago
8

color%7Bred%7D%20Question%7D%7D%7D%7D" id="TexFormula1" title=" \huge{\green}\fcolorbox{blue}{cyan}{\bf{\underline{\red{\color{red} Question}}}}" alt=" \huge{\green}\fcolorbox{blue}{cyan}{\bf{\underline{\red{\color{red} Question}}}}" align="absmiddle" class="latex-formula">
\mathsf \blue{sketch \: the \: graph \: of}
\mathsf \blue{y \geqslant x + 1}
​
Mathematics
1 answer:
madreJ [45]2 years ago
8 0

Answer:

Graph attached →

Step-by-step explanation:

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First, we use sin(a+b)=sinacosb + sinbcosa

sin(5pi/3)=sin(2pi/3+3pi/3)= sin(2pi/3+pi)= sin(2pi/3)cos(pi) +sin(pi)cos(2pi/3)

but we know that sin(pi)= 0, and cos (pi) = -1, so sin(5pi/3)= - sin(2pi/3)

now, use sin(2a)=2sinacosa, sin(5pi/3)= - sin(2pi/3)= -2sin(pi/3)cos(pi/3)

sin<span>(5pi/3)=  -2sin(pi/3)cos(pi/3)</span>

<span>sin(pi/3)= 0.86, cos(pi/3)=0.5, finally we have   </span>sin<span>(5pi/3)=  -0.86 x 0.5= -0.43</span>

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<h2>Answer:</h2>

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<span>
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