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3 years ago

A, B, C, D, and E are collinear points. AE = 34, BD = 16, and AB = BC =CD. What is the length of CE?

Mathematics

2 answers:

musickatia [10]3 years ago

6 0

Answer:

CE= 18

Step-by-step explanation:

A, B, C, D, and E are collinear points

$AE=AB +BC+CD+DE$

BD = 16, and AB = BC =CD

BD=BC+CD, BC =CD

So $BD= BC+BC$

$16=2BC$

BC= 8

$AB = BC =CD$

AB= 8, BC=8, CD= 8, E= 34

$AE=AB +BC+CD+DE$

$34=8+8+8+DE$

$34=24+DE$ , subtract 24 from both sides

DE= 10

$CE= CD+DE$

$CE= 8+10$

CE= 18

Lesechka [4]3 years ago

5 0

18. Drawn out we know that bc and cd are equal. Bd is 16 so bc and cd are both 8.

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