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Jet001 [13]
3 years ago
5

A, B, C, D, and E are collinear points. AE = 34, BD = 16, and AB = BC =CD. What is the length of CE?

Mathematics
2 answers:
musickatia [10]3 years ago
6 0

Answer:

CE= 18

Step-by-step explanation:

A, B, C, D, and E are collinear points

AE=AB +BC+CD+DE

BD = 16, and AB = BC =CD

BD=BC+CD, BC =CD

So BD= BC+BC

16=2BC

BC= 8

AB = BC =CD

AB= 8, BC=8, CD= 8, E= 34

AE=AB +BC+CD+DE

34=8+8+8+DE

34=24+DE, subtract 24 from both sides

DE= 10

CE= CD+DE

CE= 8+10

CE= 18

Lesechka [4]3 years ago
5 0
18. Drawn out we know that bc and cd are equal. Bd is 16 so bc and cd are both 8.
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